What bond vibrations and stretching frequencies should you observe in the IR spectrum of caffeine?
1 answer:
- The bond vibrations that can be observed in the IR spectrum of caffeine :
i) asymmetric, ii) symmetric, iii) wagging, iv) twisting, v) scissoring, vi) rocking
- while the observable stretching frequencies are ; 1700, 1300, 2900, 1500 and 3000.
Caffeine is a polyatomic molecule ( contains more than two atoms bonded via covalent bonds ) therefore its atoms can vibrate in three dimensions ( x, y, z ).therefore the bond vibrations that can be observed in the IR spectrum of caffeine are : asymmetric, symmetric, wagging, twisting, scissoring, and rocking.
The observable stretching frequencies that are in the IR spectrum of caffeine ; C = O is 1700 , C - H is 1300, C -H is 2900, C -N is 1500, and N -H = 3000.
Hence we can conclude The bond vibrations that can be observed in the IR spectrum of caffeine : i) asymmetric, ii) symmetric, iii) wagging, iv) twisting, v) scissoring, vi) rocking and the observable stretching frequencies are ; 1700, 1300, 2900, 1500 and 3000.
Learn more : brainly.com/question/13184210
You might be interested in
163 grams (3 sig. fig.).
<h3>Explanation</h3>- Formula of <em>carbon(IV) oxide</em> (a.k.a. carbon dioxide):
.
- Molar mass of
.
- Formula of ethyne: structural
or molecular
.
- Molar mass of
.
All carbon atoms in that 104 grams of ethyne will end up in . Number of moles of molecules in 104 grams of ethyne:
.
There are two carbon atoms in each ethyne molecule. Number of carbon atoms in that many ethyne molecules:
.
There are one carbon atom in each molecule. In case oxygen is in excess, all those carbon atoms from that 104 grams of ethyne will make
of
.
Mass of all those molecules:
. (3 sig. fig. as in the mass of ethyne.)
Explanation:
Normal moles of = volume × normal concentration
= 4.7 × 0.139 = 0.6533 mol
Moles of in hyponatremia blood = volume × hyponatremia concentration
= 4.7 × 0.116 = 0.5452 mol
Moles of NaCl to be added = moles of extra needed
= 0.6533 mol - 0.5452 mol = 0.1081 mol
Mass of NaCl = moles × molar mass of NaCl
= 0.1081 mol × 58.443
= 6.317g
= 6.32 g (approx)
Thus, we can conclude that mass of sodium chloride would need to be added to the blood is 6.32 g.