Question

Jesse travels 3.0 meters east and then turns and travels 4.0 meters north. The trip requires 35 seconds. What is his velocity?

Answer 1

B.) 0.14 m/a, northeast is your answer.

Answer 2

Answer:

0.14 m/s, northeast

Explanation:

It is given that,

Distance travelled in east direction, $x_1=3\ m$

Distance travelled in north direction, $x_2=4\ m$

The shortest path or the displacement of Jesse is, $x=\sqrt{x_1^2+x_2^2}$

$x=\sqrt{3_1^2+4_2^2}$

x = 5 m   ( in northeast direction )

Time taken, t = 35 seconds

Jesse's velocity is defined as the net displacement divided by total time taken i.e.

$v=\dfrac{x}{t}$

$v=\dfrac{5\ m}{35\ s}$

v = 0.14 m/s

So, the velocity of Jesse is 0.14 m/s and it is in northeast direction. So, the correct option is (b) "0.14 m/s, northeast".