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3 years ago

Jesse travels 3.0 meters east and then turns and travels 4.0 meters north. The trip requires 35 seconds. What is his velocity?

Chemistry

2 answers:

emmainna [20.7K]3 years ago

5 0

B.) 0.14 m/a, northeast is your answer.

Goshia [24]3 years ago

3 0

Answer:

0.14 m/s, northeast

Explanation:

It is given that,

Distance travelled in east direction, $x_1=3\ m$

Distance travelled in north direction, $x_2=4\ m$

The shortest path or the displacement of Jesse is, $x=\sqrt{x_1^2+x_2^2}$

$x=\sqrt{3_1^2+4_2^2}$

x = 5 m ( in northeast direction )

Time taken, t = 35 seconds

Jesse's velocity is defined as the net displacement divided by total time taken i.e.

$v=\dfrac{x}{t}$

$v=\dfrac{5\ m}{35\ s}$

v = 0.14 m/s

So, the velocity of Jesse is 0.14 m/s and it is in northeast direction. So, the correct option is (b) "0.14 m/s, northeast".

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Answer:

trans-1,3-pentadiene is more stable than 1,4-pentadiene due to presence of a conjugated double bond.

Explanation:

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H(diene) depends on stability of diene.

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4 years ago

If nicotine has a molar mass of 160±5g/mol , what is its molecular formula?

navik [9.2K]

Answer:

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Explanation:

I don't believe one can deduce the molecular formula from just it's molar mass. There are too many possible combinations of elements that could add to the same mass. This is the correct formula for nicotine, taken from known information, not from an analysis of the molar mass alone. One can confirm the molar mass is in the correct range:

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3 years ago

Combustion analysis of naphthelene, a hydrocarbon used in mothballs, produces 13.20g CO2 and 1.80g H2O. Calculate the empirical

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Answer: C₃H₂

Explanation:

1) Since you are told naphthelene is a hydrocarbon, you know that its chemical formula only has atoms of C and H.

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Proportion of C in 13.20 g of CO₂

12.01 g C / 44.01 g CO₂ = x / 13.20 g CO₂ ⇒

x = 13.20 g CO₂ × 12.01 g C / 44.01 g CO₂ = 3.602 g C

3) Calculate the mass of H in 1.80 g of H₂O

Atomic masses:

H: 1.01 g/mol
O: 16.0 g/mol

Molar mass H₂O = 18.02 g/mol

Proportion of H in 1.80 g H₂O

2.02 g H / 18.02 g H₂O = x / 1.80 g H₂O

x = 1.80 gH₂O × 2.02 g H / 18.02 gH₂O = 0.202 g H.

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