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ankoles [38]
3 years ago
12

A piano wire with mass 3.50 g and length 83.0 cm is stretched with a tension of 35.0 N. A wave with frequency 120 Hz and amplitu

de 1.20 mm travels along the wire.
Physics
1 answer:
Mariana [72]3 years ago
7 0

Answer:

The average power is 0.1570 W.

Explanation:

Given that,

Mass of piano wire = 3.50 g

Length = 83.0 cm

Tension = 35.0 N

Frequency = 120 Hz

Amplitude = 1.20 mm

Suppose we need to calculate the average power carried by the wave

We need to calculate the angular frequency

Using formula of frequency

\omega=2\pi f

\omega=2\times\pi\times120

\omega=753.9\ rad/s

We need to calculate the linear density

Using formula of linear density

\mu=\dfrac{M}{l}

Put the value into the formula

\mu=\dfrac{3.50\times10^{-3}}{83\times10^{-2}}

\mu=0.00421\ kg/m

\mu=4.21\times10^{-3}\ kg/m

We need to calculate the average power

Using formula of average power

P_{avg}=\dfrac{1}{2}\sqrt{\mu T}\omega^2\times A^2

Put the value into the formula

P_{avg}=\dfrac{1}{2}\sqrt{4.21\times10^{-3}\times35.0}\times(753.9)^2\times(1.20\times10^{-3})^2

P_{avg}=0.1570\ W

Hence, The average power is 0.1570 W.

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pochemuha

Answer:

v = u + a t

80 = 50 + a * 30

80 - 50 /30 = a

a = 30/30 = 1 m /s 2

s = u t + 1/2 at ^2

s = 50 * 30 + 1/2 * 1 * 30^2

s = 1500 + 1/2 * 900

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s = 1950 m

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How many excess electrons are on a ball with a charge of -1.4944 10-16 C?
agasfer [191]

Answer:

There are 934 excess electrons on the ball with charge -1.4944*10^(-16).

Step-by-Step Explanation:

A ball will usually be neutral and have no charge on it.

If it is negatively charged, it means there are excess electrons on it.

If we know the charge on the ball, we can count the excess no. of electrons.

We know that the charge on the ball = c = -1.4944*10^-16

Charge of one electron = e = 1.6*10^-19

Charge of n electrons on the ball = ne = c

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n = (-1.4944*10^-16)/(1.6*10^-19)

n = 934 electrons

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3 years ago
A water tank has a square base of area 8 square meters. Initially the tank contains 70 cubic meters. Water leaves the tank, star
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Answer:

Explanation:

Given

base of water tank A=8\ m^2

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Water leaves the tank at the rate of

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Integrating rate to get desired volume

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therefore

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V-70=2t+2t^2|_0^3

V-70=-24

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and volume=Area\times h

h=\frac{V}{A}

h=\frac{46}{8}

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