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3 years ago

A truck speeds up from velocity of 6m/s to 14m/s in 4 seconds. what is the trucks acceleration?

Physics

1 answer:

Tanzania [10]3 years ago

3 0

To calculate the acceleration of the truck, we use the equation of motion

$v = u + at$

Here, v is final velocity of the truck, u is initial velocity of truck, a is acceleration of the truck and t is time taken.

Given, u = 6 m/s, v = 14 m/s and t = 4 s.

Substituting these values in above equation, we get

$14 \ m/s = 6 \ m/s + a \times 4 \ s \\\\ a = \frac{14 \ m/s - 6 \ m/s}{ 4 \ s } = 2 \ m /s^2$ .

Thus, the truck acceleration is $2 \ m /s^2$

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A transformer is intended to decrease the value of the alternating current from 500 amperes to 25 amperes. The primary coil cont

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Answer:

The number of turns in secondary coil is 4000

Explanation:

Given:

Current in primary coil $I_{P} = 500$ A

Current in secondary coil $I_{S} = 25$ A

Number of turns in primary coil $N_{P} = 200$

In case of transformer the relation between current and number of turns is given by,

$\frac{N_{S} }{N_{P} } = \frac{I_{P} }{I_{S} }$

For finding number of turns in secondary coil,

$N_{S} = \frac{I_{P} }{I_{S} } N_{P}$

$N_{S} = \frac{500}{25} \times 200$

$N_{S} = 4000$

Therefore, the number of turns in secondary coil is 4000

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2 years ago

g A cylinder of mass m is free to slide in a vertical tube. The kinetic friction force between the cylinder and the walls of the

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Answer:

The vertical distance is $d = \frac{2}{k} *[mg + f]$

Explanation:

From the question we are told that

The mass of the cylinder is m

The kinetic frictional force is f

Generally from the work energy theorem

$E = P + W_f$

Here E the the energy of the spring which is increasing and this is mathematically represented as

$E = \frac{1}{2} * k * d^2$

Here k is the spring constant

P is the potential energy of the cylinder which is mathematically represented as

$P = mgd$

And

$W_f$ is the workdone by friction which is mathematically represented as

$W_f = f * d$

$\frac{1}{2} * k * d^2 = mgd + f * d$

=> $\frac{1}{2} * k * d^2 = d[mg + f ]$

=> $\frac{1}{2} * k * d = [mg + f ]$

=> $d = \frac{2}{k} *[mg + f]$

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Answer:

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When an object is balanced about a pivot, the total clockwise moment must be equal to the total __________ __________. What two

Keith_Richards [23]

Answer:

When an object is balanced, about a pivot, the total clockwise moment must be equal to the total anticlockwise moment about that pivot.