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zaharov [31]
4 years ago
6

A truck speeds up from velocity of 6m/s to 14m/s in 4 seconds. what is the trucks acceleration?

Physics
1 answer:
Tanzania [10]4 years ago
3 0

To calculate the acceleration of the truck, we use the equation of motion

v = u + at

Here, v is final velocity of the truck, u is initial velocity of truck, a is acceleration of the truck and t is time taken.

Given,  u = 6 m/s, v = 14 m/s and t = 4 s.

Substituting these values in above equation, we get

14 \ m/s = 6 \ m/s + a \times 4 \ s \\\\  a = \frac{14 \ m/s - 6 \ m/s}{ 4 \ s } =  2 \ m /s^2.

Thus,  the truck acceleration is 2 \ m /s^2

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Explanation:

Given that:

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But it seems the value of the distance ran west is wrong , because i do not think he can run  2218km under 1.2hours considering he ran 567.5m due east at 2.3hours .

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Two particles each of mass m and charge q are suspended by strings of length / from a common point. Find the angle e that each s
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Answer:

\theta =\left (\frac{kq^{2}}{4L^{2}\times mg}  \right )^{\frac{1}{3}}

Explanation:

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T Cosθ = mg     .......(2)

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\theta ^{3} =\frac{kq^{2}}{4L^{2}\times mg}

\theta =\left (\frac{kq^{2}}{4L^{2}\times mg}  \right )^{\frac{1}{3}}

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