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PSYCHO15rus [73]
3 years ago
14

Which formula equation shows a reversible reaction? 2 upper N a plus upper F subscript 2 right arrow 2 upper N a upper F. Upper

C a upper C upper O subscript 3 right arrow upper C a upper O plus upper C upper O subscript 2. Upper N upper H subscript 4 upper C l (s) right and left arrows stacked above each other upper N upper H subscript 3 (g) plus upper H upper C l (g). 2 upper H subscript 2 upper O subscript 2 (a q) right arrow with upper P t above it 2 upper H subscript 2 upper O (l) plus upper 2 subscript 2 (g).
Chemistry
2 answers:
Tamiku [17]3 years ago
4 0

Upper N upper H subscript 4 upper C l (s) right and left arrows stacked above each other upper N upper H subscript 3 (g) plus upper H upper C l (g)

Explanation:

The given equation is;

  NH₄Cl    ⇄      NH₃   +    HCl

This equation is clearly different from the other ones.

  • In the reactant going forward, there is a right and left arrows stacked above each other.
  • The symbol is  ⇄  and it is used to show reversibility of chemical reactions.

learn more:

Chemical reactions brainly.com/question/3953793

#learnwithBrainly

svetlana [45]3 years ago
3 0

Answer:

b is the answer

Explanation:

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One of the most likely products for the reaction would be Ag_2O

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The reaction between AgNO_3 and NaOH yields 3 products which are Ag_2O (a precipitate), NaNO_3, and H_2O as shown by the equation below:

2 AgNO_3 + 2 NaOH --- > Ag_2O + 2 NaNO_3 + H_2O

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Answer: The empirical formula for the given compound is CH_2

Explanation:

The chemical equation for the combustion of compound having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of CO_2=22.0g

We know that:

Molar mass of carbon dioxide = 44 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 22.0 g of carbon dioxide, \frac{12}{44}\times 22.0=6g of carbon will be contained.

For calculating the mass of hydrogen:

Mass of hydrogen = Mass of sample - Mass of carbon

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Mass of hydrogen = 1.0 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{6g}{12g/mole}=0.5moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.0g}{1g/mole}=1.0moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.

For Carbon = \frac{0.5}{0.5}=1

For Hydrogen  = \frac{1.0}{0.5}=2

Step 3: Taking the mole ratio as their subscripts.

The ratio of Fe : C : H = 1 : 2

Hence, the empirical formula for the given compound is C_{1}H_{2}=CH_2

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Despite the superior intellect of our lab workers, none of the problems above actually caused the discrepancies. This occurs som
Soloha48 [4]

Answer:

Haven't evaporated all of the water

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One of the main sources of error that occur in a formula of a hydrate lab is that all of the water is not evaporated. We can see at the end of the video that half of the CoCl2 is a light blue colors and the other half is a dark blue color. This indicates that all of the water still has not been evaporated off, resulting in the actual mass of the salt to be greater than the predicted value.

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