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drek231 [11]
3 years ago
7

Free points if you help me with my work!

Chemistry
2 answers:
CaHeK987 [17]3 years ago
6 0

Answer:

Ok

Explanation:

svet-max [94.6K]3 years ago
3 0

Answer:

how can I get free points?

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Name the two possible products in the precipitation reaction of copper (II) chloride and sodium phosphate. Use the charges on th
satela [25.4K]

Answer:

General equation for a double-displacement reaction:  

AB + CD --> AC + BD

• sodium chloride – NaCl copper sulfate – CuSO₄  

NaCl + CuSO₄ --> Na₂SO₄ + CuCl₂

The products formed are sodium sulfate and copper (II) chloride.

Copper (II) chloride forms a blue colored solution.

• sodium hydroxide – NaOH copper sulfate – CuSO₄  

NaOH + CuSO₄ --> Na₂SO₄ + Cu(OH)₂

The products formed are sodium sulfate and copper (II) hydroxide.

Copper (II) hydroxide forms a blue colored solution.

• sodium phosphate – Na₂HPO₂ copper sulfate – CuSO₄  

Na₂HPO₄ + CuSO₄ --> Na₂SO₄ + CuHPO₄

The products formed are sodium sulfate and copper (II) hydrogen phosphate.

Copper (II) hydrogen phosphate forms a blue colored solution.

• sodium chloride – NaCl silver nitrate – AgNO₃  

NaCl + AgNO₃--> AgCl + NaNO₃

The products formed are silver chloride and sodium nitrate.

Silver chloride forms a white precipitate.

• sodium hydroxide – NaOH silver nitrate – AgNO₃  

NaOH + AgNO₃   --> NaNO₃ + AgOH

The products formed are silver hydroxide and sodium nitrate.

Silver hydroxide forms a white precipitate.

• sodium phosphate – Na₂HPO₄ silver nitrate – AgNO₃

Na₂HPO₄ + AgNO₃  --> NaNO₃ +  Ag₂HPO₄

The products formed are sodium nitrate and silver hydrogen phosphate.

Silver hydrogen phosphate forms a colorless solution.

Explanation:

5 0
3 years ago
8.
Dima020 [189]
The correct answer is b hope this helps air
5 0
3 years ago
A 1.00 liter solution contains 0.31 M hydrocyanic acid and 0.40 M sodium cyanide. If 0.100 moles of barium hydroxide are added t
andriy [413]

Explanation:

acid --> HCN

base --> KCN

now

another base NaOH is added

we know that

base will react with an acid

so

OH- + HCN ---> CN- + H20

we can see that

HCN is used up , so number of moles of HCN will decrease

CN- is being formed , so number of moles of CN- will increase.

A  false

B  false

C  false

D  true

E  false

6 0
3 years ago
Complete the given equation and mention whether heat is absorbed or evolved during the chemical reaction.
DaniilM [7]

Answer:

NaCI + H2O

this is answer

5 0
2 years ago
Lead(II) chromate, PbCrO4, is a yellow paint pigment (called chrome yellow) prepared by a precipitation reaction. In a preparati
Roman55 [17]

Answer:

n = 0.1624 moles

Explanation:

n=\frac{m}{M} \\n=\frac{52.5}{323.1937} \\n= 0.1624 mol

8 0
3 years ago
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