Radiation fog is the fog that is formed when the heat absorbed the Earth's surface is released into the atmosphere producing fog. This only occurs when the air is clear and calm. In the center of an anticyclone, the conditions of the air are clear and calm which is favorable for the formation of radiation fog. The center of cyclones, on the other hand, is turbulent and cloudy which prevents the formation of radiation fogs.
Answer:
71.4583 Hz
67.9064 N
Explanation:
L = Length of tube = 1.2 m
l = Length of wire = 0.35 m
m = Mass of wire = 9.5 g
v = Speed of sound in air = 343 m/s
The fundamental frequency of the tube (closed at one end) is given by

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz
The linear density of the wire is

The fundamental frequency of the wire is given by

The tension in the wire is 67.9064 N
When a relationship between two different things is shown in a fraction it is a ratio.
hope this helps :)
Answer:
6.7 m/s^2
Explanation:
The formula of acceleration is:

where
is acceleration,
is velocity and
is time.
means final velocity.
means initial velocity,
means final time and
means initial time.
We are given that the Firebird travels at velocity of 0 to 60 mph in four seconds. Therefore:
- Our initial velocity starts at 0 mph.
- Our final velocity is at 60 mph.
- Our initial time is 0 second.
- Our final time is 4 seconds.
Since it travels to the east then our vector will be positive. However, acceleration has to be in m/s^2 unit (Sl unit) so we'll have to convert from mph (miles per hours) to m/s (meters per second) first.
We know that:
- A mile equals to 1609.344 meters.
- An hour equals to 60 minutes which a minute equals to 60 seconds. So 60 minutes will equal to 3600 seconds.
Now we divide 1609.344 by 3600 to find a unit rate of m/s:

Now multiply 0.44704 m/s by 0 and 60 to get velocity in m/s unit:
- Initial velocity = 0 m/s
- Final velocity = 60 * 0.44704 = 26.82 m/s
Time is already in second so no need for conversion. Substitute known information in the formula:

Therefore, the Firebird will accelerate at the rate of 6.7 m/s^2.
Answer:
Part a)

Part b)

Part c)

Explanation:
Part a)
Moment of inertia of the system about an axis passing through B and C is given as




Part b)
Moment of inertia of the system about an axis passing through A and C is given as




Part c)
Moment of inertia of the system about an axis passing through the center of the square and perpendicular to the plane of the square



