Answer:
Answer is A
Explanation:
As we know , for constant velocity we get a straight line.
The formula for this problem is s = vt which is similar to a straight line formula like y = mx + c.
If we put here c = 0 we get the formula for distance and velocity.
So the answer is A.
The longest distance that a person can swim is 5.64 m.
<h3>What is the longest distance?</h3>
We know that the diameter of a circle is a line that is drawn from one point to another in the circle. Now we are told that the pool is circular in nature. That implies that the longest that a person can swim could be obtained form the diameter of the circle.
Given that;
A = πr^2
A = area of teh circular pool
r = radius of the pool
r = √A/ π
r = √25/3.142
r = 2.82m
Diameter of the circular pool = 2 r = 2 (2.82 cm) = 5.64 m
Learn more about circle:brainly.com/question/11833983
#SPJ1
Missing parts;
An ad for an above-ground pool states that it is 25 m2. From the ad, you can tell that the pool is a circle. If you swim from one point at the edge of the pool to another, along a straight line, what is the longest distance d you can swim? Express your answer in three significant figures.
Answer:
Measuring cup and graduated cylinder
Explanation:
These tools measure the volume of liquid matter. Measuring cups are used frequently in cooking and provide measurements generally in ounces and grams. A graduated cylinder is used in laboratories and in research and allows for a greater degree of precision in measuring the volume.
Answer:
Explanation:
Given that,
Hot temperature
T_H = 96°F
From Fahrenheit to kelvin
°K = (°F - 32) × 5/9 + 273
°K = (96 - 32) × 5/9 + 273
K = 64 × 5/9 + 273 = 35.56 + 273
K = 308.56 K
T_H = 308.56 K
Low temperature
T_L = 70°F
Same procedure to Levine
T_L = (70-32) × 5/9 + 273
T_L = 294.11 K
A carnot refrigerator working between a hot reservoir and at temperature T_H and a cold reservoir and at temperature T_L has a coefficient of performance K given by
K = T_L / (T_H - T_L)
K = 294.11 / (308.56 - 294.11)
K = 294.11 / 14.45
K = 20.36
Then, the coefficient of performance is the energy Q_L drawn from the cold reservoir as heat divided by work done,
So, for each joules W = 1J
K = Q_L / W
Then,
Q_L = K•W
Q_L = 20.36 × 1
Q_L = 20.36 J
Q_L ≈ 20J
So, approximately 20J of heats are removed from the room
The acceleration is given by:
a = v²/r
a = 10²/5
a = 20 m/s²
This is not a realistic value for a runner because it is very large.