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mel-nik [20]
3 years ago
14

State which statement is a physical change or a chemical change:

Chemistry
1 answer:
Oliga [24]3 years ago
4 0

Answer:

Physical change: A,C ,D, F, H, I

Chemical Change: B, E, G, J, K

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GIVING BRAINLEST WITH WHOEVER HAS THE RIGHT ANSWER! Plz and Tysm.
WINSTONCH [101]
Oceanic crust is more dense because it contains basalt which is more dense than granite which composes the continental crust.
6 0
3 years ago
Given 50g and 27ml find density
Airida [17]

Answer:

1.85g per cubic centimeter (g/cm3

Explanation:

because density=mass/volume, so it will be 50g divide by 27ml =. 1.85g/cm3

5 0
1 year ago
What is the relative atomic mass of an element
Gennadij [26K]

Answer:

20.2 amu.

Explanation:

Let A represent isotope ²⁰X

Let B represent isotope ²²X

From the question given above, the following data were obtained:

For Isotope A (²⁰X):

Mass of A = 20

Abundance (A%) = 90%

For Isotope B (²²X):

Mass of B = 22

Abundance (A%) = 10%

Relative atomic mass (RAM) =?

The relative atomic mass (RAM) of the element can be obtained as follow:

RAM = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]

RAM = [(20 × 90)/100] + [(22 × 10)/100]

RAM = 18 + 2.2

RAM = 20.2 amu

Thus, relative atomic mass (RAM) of the element is 20.2 amu

4 0
3 years ago
A gold-colored ring has a mass of 17.5 grams and a volume of 0.82 mL. What is the density of this ring?
max2010maxim [7]

Answer:

21 g/mL

Explanation:

To solve this problem, first look at the density equation, which is D=M/V, which D stands for density, M stands for mass, and V stands for volume. When you substitute in the variables, you get D=17.5/.82, which is equivalent to 21.34. However, since we need to pay attention to the sig fig rules for multiplying, we need to have the same amount of sig figs as the value with the least amount of sig figs, which is the number .82. .82 has two sig figs, so you round down. Your answer will be 21 g/mL.

4 0
3 years ago
What is the mass of 11.4 L of NO2
kodGreya [7K]
At STP volume is 22.4 L

Molar mass NO₂ = 46.0 g/mol

1 mole ---------- 22.4 L
? mole ---------- 11.4 L

moles = 11.4 * 1 / 22.4

moles = 11.4 / 22.4

= 0.5089 moles of NO₂

Mass NO₂ :

moles NO₂ * molar mass

0.5089 * 46.0

= 23.4094 g of NO₂

hope this helps!

7 0
3 years ago
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