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PtichkaEL [24]
4 years ago
14

The general formula for ____________ and ____________ are cnh2n+2 and cnh2n , respectively. axial and equatorial hydrogen atoms

are interconverted during a ____________ . the anti conformation is ____________ in energy than a gauche conformation. the increase in energy when tetrahedral bond angles deviate from the optimum angle of 109.5° is known as ____________ strain.
Chemistry
1 answer:
Anuta_ua [19.1K]4 years ago
4 0

The general formula for alkane and cycloalkane are C_{n}H_{2n+2} and C_{n}H_{2n}, respectively.

Axial and equatorial hydrogen atoms are inter-converted during a ring flip .

The anti conformation is lower in energy than a gauche conformation.

The increase in energy when tetrahedral bond angles deviate from the optimum angle of 109.5° is known as angle strain.

Now,

Alkanes are saturated hydrocarbon with general formula C_{n}H_{2n+2} and cycloalkanes are also saturated cyclic hydrocarbons where carbons are linked  in the form of a ring with general formula C_{n}H_{2n}.

The phenomenon which involves the inter-conversion of axial hydrogen atoms into equatorial hydrogen atoms is said to be ring flip.

The energy of the anti conformation is lower than the gauche conformation due to steric strain, which is lower in anti conformation and results in low energy.

The increase in potential energy of the molecule because of the deviation of bond angles from its original values is said to be angle strain.

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17.65 grams of O2 are needed for a complete reaction.

Explanation:

You know the reaction:

4 NH₃ + 5 O₂ --------> 4 NO + 6 H₂O

First you must know the mass that reacts by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction). For that you must first know the reacting mass of each compound. You know the values ​​of the atomic mass of each element that form the compounds:

  • N: 14 g/mol
  • H: 1 g/mol
  • O: 16 g/mol

So, the molar mass of the compounds in the reaction is:

  • NH₃: 14 g/mol + 3*1 g/mol= 17 g/mol
  • O₂: 2*16 g/mol= 32 g/mol
  • NO: 14 g/mol + 16 g/mol= 30 g/mol
  • H₂O: 2*1 g/mol + 16 g/mol= 18 g/mol

By stoichiometry, they react and occur in moles:

  • NH₃: 4 moles
  • O₂: 5 moles
  • NO: 4 moles
  • H₂O: 6 moles

Then in mass, by stoichiomatry they react and occur:

  • NH₃: 4 moles*17 g/mol= 68 g
  • O₂: 5 moles*32 g/mol= 160 g
  • NO: 4 moles*30 g/mol= 120 g
  • H₂O: 6 moles*18 g/mol= 108 g

Now to calculate the necessary mass of O₂ for a complete reaction, the rule of three is applied as follows: if by stoichiometry 68 g of NH₃ react with 160 g of O₂, 7.5 g of NH₃ with how many grams of O₂ will it react?

mass of O_{2} =\frac{7.5 g of NH_{3} * 160 g of O_{2} }{68 g of NH_{3} }

mass of O₂≅17.65 g

<u><em>17.65 grams of O2 are needed for a complete reaction.</em></u>

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