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PtichkaEL [24]
3 years ago
14

The general formula for ____________ and ____________ are cnh2n+2 and cnh2n , respectively. axial and equatorial hydrogen atoms

are interconverted during a ____________ . the anti conformation is ____________ in energy than a gauche conformation. the increase in energy when tetrahedral bond angles deviate from the optimum angle of 109.5° is known as ____________ strain.
Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
4 0

The general formula for alkane and cycloalkane are C_{n}H_{2n+2} and C_{n}H_{2n}, respectively.

Axial and equatorial hydrogen atoms are inter-converted during a ring flip .

The anti conformation is lower in energy than a gauche conformation.

The increase in energy when tetrahedral bond angles deviate from the optimum angle of 109.5° is known as angle strain.

Now,

Alkanes are saturated hydrocarbon with general formula C_{n}H_{2n+2} and cycloalkanes are also saturated cyclic hydrocarbons where carbons are linked  in the form of a ring with general formula C_{n}H_{2n}.

The phenomenon which involves the inter-conversion of axial hydrogen atoms into equatorial hydrogen atoms is said to be ring flip.

The energy of the anti conformation is lower than the gauche conformation due to steric strain, which is lower in anti conformation and results in low energy.

The increase in potential energy of the molecule because of the deviation of bond angles from its original values is said to be angle strain.

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he mass defect of the helium nucleus ⁴He₂ is 0.030377 u

Further explanation

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Δm = mass defect ( u )

mp = mass of proton ( u )

me = mass of electron ( u )

mn = mass of neutron ( u )

M = atomic mass ( u )

A = mass number

Z = atomic number

Let us now tackle the problem !

Given :

Unknown :

Δm = ?

Solution :

Learn more

Rutherford’s major achievements : brainly.com/question/1552732

Unit of radius of an atom : brainly.com/question/1968819

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Answer details

Grade: College

Subject: Physics

Chapter: Nuclear Physics

Keywords: Mass , Defect , Nucleon , Number , Atomic , Proton , Electron , Neutron

4 0
2 years ago
how does the main function of the nervous system help the body react to internal and external stimuli??
Irina-Kira [14]
Nerves send signals to your brain from your spinal cord. If something is burning your nerves will send a pain signal from the area of the burn to your brain through you spinal cord. Then your brain sends a signal back to the nerves that there is pain and you should avoid it. Same with internal nerves and same with touch.
6 0
2 years ago
A 500.0-mL buffer solution is 0.100 M in HNO2 and 0.150 M in KNO2. Determine whether each addition would exceed the capacity of
Leviafan [203]

Answer:

None of the additions will exceed the capacity of the buffer.

Explanation:

As we know a buffer has the ability to resist pH changes when small amounts of strong acid or base are added.

The pH of the buffer is given by the Henderson-Hasselbach equation:

pH = pKa + log [A⁻] / [HA]

where A⁻ is the conjugate base of the weak acid HA.

Now we can see that what is important is the ratio [A⁻] / [HA] to resist a pH change brought about by the addition of acid or base.

It follows then that once we have consumed by neutralization reaction either the acid or conjugate base in the buffer, this will lose its ability to act as such and the pH will increase or decrease dramatically by any added acid or base.

Therefore to solve this question we must determine the number of moles of acid HNO₂ and NO₂⁻ we have in the buffer and compare it with the added acid or base to see if it will deplete one of these species.

Volume buffer = 500.0 mL = 0.5 L

# mol HNO₂ = 0.5 L x 0.100 mol/L = 0.05 mol HNO₂

# mol NO₂⁻ = 0.5 L x 0.150 mol/L = 0.075 mol NO₂⁻

a. If we add 250 mg NaOH (0.250 g)

molar mass NaOH =40 g/mol

# mol NaOH =0.250 g/ 40g/mol = 0.0063 mol

0.0063 mol NaOH will be neutralized by 0.0063 mol HNO₂ and we have plenty of it, so it would not exceed the capacity of the buffer.

b. If we add 350 mg KOH (0.350 g)

molar mass KOH =56.10 g

# mol KOH = 0.350 g/56.10 g/mol = 0.0062 mol

Again the capacity of the buffer will not be exceeded since we have 0.05 mol HNO₂ in the buffer.

c. If we add 1.25 g HBr

molar mass HBr = 80.91 g/mol

# mol HBr = 1.25 g / 80.91 g/mol = 0.015 mol

0.015 mol Hbr will neutralize 0.015 mol NO₂⁻ and we have to start with 0.075 mol in the buffer, therefore the capacity will not be exceeded.

d. If we add 1.35 g HI

molar mass HI = 127.91 g/mol

# mol HI = 1.35 g / 127.91 g/mol = 0.011 mol

Again the capacity of the buffer will not be exceed since we have plenty of it in the buffer after the neutralization reaction.

7 0
2 years ago
There are two different compounds of sulfur and fluorine.
weqwewe [10]
Atomic mass of F: 19.0 g/mol

Atomic mass of S: 32.1 g/mol

1.18 g F = [1.18 g / 19.0 g / mol] = 0.062  mol F

1 g S =  1 g/ 32.1 g/mol = 0.031  mol S

Divide by 0.031

0.062 mol F / 0.031 = 2  mol F

0.031 mol S / 0.031 = 1 mol S

SF2 Then X = 2

Verification:
F2 = 2*19.0 g = 38 g F
S = 32.1 g

36 gF / 32.1 g S = 1.18 g F / g S



7 0
3 years ago
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Nadusha1986 [10]
.3 liters... im pretty sure this is correct!!
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3 years ago
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