Apply conservation of energy; the pendulum's maximum potential energy (at the highest point of its motion) equals the maximum kinetic energy (at the lowest point of its motion):
Max PE = Max KE
We will calculate the max PE, ie the potential energy after that ball is lifted up:
Max PE = mgh
PE is the potential energy, m is the ball's mass, g is acceleration due to earth's gravity, and h is the height.
Given values:
m = 2kg
g = 9.81m/s²
h = 1.5m
Plug in the values and solve for Max PE:
Max PE = 2(9.81)(1.5)
Max PE = 29.43J
The ball's kinetic energy is given by:
KE = 0.5mv²
We know the ball's velocity is greatest when it attains Max KE, and the max KE equals the Max PE:
Max KE = Max PE = 29.43J = 0.5mv²
Given values:
m = 2kg
Now plug in and solve for v:
2v² = 58.86
v = 5.425
v = 5.4m/s
Answer:
Explanation:
Hello,
In this case, since the acceleration in terms of position is defined as its second derivative:
The purpose here is derive x(t) twice as follows:
Thus, the acceleration turns out 4.8 meters per squared seconds.
Best regards.
Answer:
8.25 x 10^-3 V/m
Explanation:
Resistivity, ρ = 2.44 x 10^-8 Ohm m, Diameter = 1.8 mm
radius, r = 0.9 mm = 0.9 x 10^-3 m, l = 40 cm = 0.4 m, i = 860 mA = 0.86 A,
Let V be the potential difference and E be the electric field.
Use the formula for resistance
R = ρ l / A
R = (2.44 x 10^-8 x 0.4) / ( 3.14 x 0.9 x 0.9 x 10^-6)
R = 3.84 x 10^-3 ohm
According to Ohm's law
V = i x R
V = 0.860 x 3.84 x 10^-3 Volt = 3.3 x 10^-3 Volt
E = V / l = 3.3 x 10^-3 / 0.4 = 8.25 x 10^-3 V/m
The sign of the charged particle is positively charged.
<h3>What is potential difference?</h3>
- When a single charge is transported in an electric field, work is done by the potential difference (also known as electrical potential).
- There is potential energy stored in this charge that could flow when work is done on it.
- Voltage is the possibility of a single charge flowing. The need to flow increases with voltage.
- Here, voltage can be the potential differences.
The potential difference between the 2 points determines the movement of that particle. An electron moves from lower to higher potential which is negatively charged, and a positively charged particle moves from higher to lower potential.
Now, since the particle is moving from a point A having 160 v potential to point B having 100 v potential that is it is moving from higher potential to a lower potential therefore the particle will be a positively charged one.
Learn more about potential difference,
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Answer:
a = 0.009 J
b = 0.19 m/s
c = 0.005 J and 0.004 J
Explanation:
Given that
Mass of the object, m = 0.5 kg
Spring constant of the spring, k = 20 N/m
Amplitude of the motion, A = 3 cm = 0.03 m
Displacement of the system, x = 2 cm = 0.02 m
a
Total energy of the system, E =
E = 1/2 * k * A²
E = 1/2 * 20 * 0.03²
E = 10 * 0.0009
E = 0.009 J
b
E = 1/2 * k * A² = 1/2 * m * v(max)²
1/2 * m * v(max)² = 0.009
1/2 * 0.5 * v(max)² = 0.009
v(max)² = 0.009 * 2/0.5
v(max)² = 0.018 / 0.5
v(max)² = 0.036
v(max) = √0.036
v(max) = 0.19 m/s
c
V = ±√[(k/m) * (A² - x²)]
V = ±√[(20/0.5) * (0.03² - 0.02²)]
V = ±√(40 * 0.0005)
V = ±√0.02
V = ±0.141 m/s
Kinetic Energy, K = 1/2 * m * v²
K = 1/2 * 0.5 * 0.141²
K = 1/4 * 0.02
K = 0.005 J
Potential Energy, P = 1/2 * k * x²
P = 1/2 * 20 * 0.02²
P = 10 * 0.0004
P = 0.004 J