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Eddi Din [679]
3 years ago
14

What are some examples of wave refractions?

Physics
1 answer:
aleksandr82 [10.1K]3 years ago
3 0
And exAMPLE WOULD BE SOUND WAVES

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Two people on ice skates push against each other. The person on the left is 50kg, the person on the right is 60kg. If the person
Zarrin [17]

I got -3.6 m/s but I had to do conservation of momentum for this question. Which involves Newtons third law but with simply that law I do not know how to complete this question. If you would like me to post my work I will though! Sorry

6 0
3 years ago
A 425-g piece of metal at 100°C is dropped into a 100-g aluminum cup containing 500 g of water at 15°C. The final temperature of
yKpoI14uk [10]

The specific heat of the metal, assuming no heat is exchanged with the surroundings is 2140 J/(kg•K).

<h3>Specific heat capacity of the metal</h3>

The specific heat capacity of the metal is determined from the principle of conservation of energy.

energy lost by the metal = energy gained by aluminum + energy gained by water

Q = mcΔθ

where;

  • m is mass (kg)
  • c is specific heat capacity
  • Δθ is change in temperature

0.425c(100 - 40) = 0.1(900)(40 - 15) + 0.5(4186)(40 - 15)

25.5c = 2250 + 52,325

c = 54,575/25.5

c = 2140 J/(kg•K)

Learn more about specific heat capacity here: brainly.com/question/21406849

#SPJ1

5 0
2 years ago
URGENT
Gemiola [76]

Answer:

5.25 J

Explanation:

W = PE = (f)(x)

PE = 35N*0.15m

PE = 5.25 N*m

1 N*m = 1 J

PE = 5.25 J

7 0
3 years ago
A fish finder uses a sonar device that sends 20,000-Hz sound pulses downward from the bottom of the boat, and then detects echoe
mrs_skeptik [129]

Answer:  The minimum time between pulses (in fresh water)

= 0.3106 s

Explanation:

To calculate the speed of echoes sounds, we will use

Speed = 2x/t

Where x = distance and t = total time.

Please note that:

sound travels at 343 m/s in air. But it travels at 1,481 m/s in water (almost 4.3 times as fast as in air); 

Total distance = 2 × 230 = 460m

Using speed of sound in water

1481 = 460/t

t = 460/1481

t = 0.3106

3 0
3 years ago
A piano emits frequencies that range from a low of about 28 hertz to a high of about 4200 hz.find the range of wavelength in air
AVprozaik [17]
The solution for this problem is:
A velocity of wave is given as V = λ⋅f
V - velocity of wave
f - frequency of wave
λ -  wave length

So getting the wave length is:
λ = V/f
λminimum = V / fmaximum
λminimum = 342 / 4200
λminimum = 0.081 m

λmaximum = V/ fminimum
λmaximum = 342 / 28
λmaximum = 12.214 m
3 0
4 years ago
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