By Newton's second law,
<em>n</em> + (-<em>w</em>) = 0
<em>p</em> + (-<em>f</em> ) = (20 kg) (2 m/s²)
where <em>n</em> is the magnitude of the normal force, <em>w</em> is the weight of the box, <em>p</em> is the magnitude of the applied force (<em>p</em> for <u>p</u>ush or <u>p</u>ull), and <em>f</em> is the magnitude of the friction force.
Calculate the weight of the box:
<em>w</em> = (20 kg) (9.80 m/s²) = 196 N
Then
<em>n</em> = <em>w</em> = 196 N
and
<em>f</em> = <em>µ</em> <em>n</em> = 0.5 (196 N) = 98 N
Now solve for <em>p</em> :
<em>p</em> - 98 N = 40 N
<em>p</em> = 138 N
Answer:
The period is 9.9 seconds
Explanation:
The period (T) of a mass (m) attached to a spring with spring constant k is:
(1)
So, if the mas is M we have that:
(2)
Now if we double the mass:
(3)
Because spring constant doesn’t change, we note that the term on (3) is equal to the right side of (2), so we have:
The answer to your question is a nonelectrolyte.
Answer:
6.8 eV
Explanation:
As you know, momentum (P) equals the mass of an object (M) times its velocity (V)
p=mv
Also, the momentum of the particle can be expressed in terms of the radius,
charge and field:
p=mv = qrB
K.Emax = p²/2m= q²r²B²/ 2m
K.Emax= (1.6x)² x (0.0104)² x (6.50 x)² / (2 x 9.1x)
K.E max= 1.16 x / 1.82 x
K.Emax= 6.37 J
work function 'Ф' = E- K.E max
since E= hc/ λ
Ф= hc/ λ - K.E max =>
Ф = 1.09 x J
Ф = 1.09 x / 1.6x
Ф =6.8 eV
Therefore, the work function of the metal is 6.8 eV