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9966 [12]
3 years ago
9

Atmosphere in a sealed space craft contains

Physics
1 answer:
Alekssandra [29.7K]3 years ago
8 0
The best and most correct answer among the choices provided by your question is the fourth choice or letter D.

<span>Atmosphere in a sealed space craft contains </span><span>pressurized atmospheric air available normally on earth.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Sally is on a canoe that comes to a stop a small distance from the dock. Since it is such a small distance, Sally decides to jum
natita [175]

Answer:

 v₂> v₃  velocity canoe is more than velocity fishing boat

Explanation:

For this exercise we must define a system consisting of the girl, Sally and the boat, in one case the canoe and in the other the fishing boat; for this system we can use moment conservation

Initial moment. Before the jump

           p₀ = (M + m₂) v

Final moment. After the jump

          p_{f} = M v₁ - m₂ v₂

Where m and v are the masses and speed of the canoe

          p₀ = p_{f}

          (M + m₂) v = M v₁ - m₂ v₂

In the case of changing the canoe for the heaviest fishing boat, the final moment is

          p_{f} = M v₁ - m₃ v₃

          p₀ = p_{f}

           (M + m₃) v = M v₁ - m₃ v₃

Since the canoe is stopped the speed v = 0, we write the speed of each boat

Canoe

          0 = M v₁ - m₂ v₂

          v₂ = M / m₂ v₁

Fishing boat

        0 = M v₁ - m₃ v₃

        v₃ = M / m₃ v₁

Since the masses of the fishing boat (m₃) is greater than the mass of the canoe (m₂) the speed of the fishing boat is less than the speed of the canoe, we can find the relationship between the two speeds

        v₂ / v₃ = m₃ / m₂

Here you can see what  v₂> v₃  velocity canoe is more than velocity fishing boat

8 0
3 years ago
All of the following are a characteristic of science except
Readme [11.4K]
No. It is D. Science is actually testable. That is the purpose of the scientific method: to TEST a theory. For something to be considered science, you must be able to observe, ask questions, develop questions, and test them. Thefore, it is a process. Lastly, yes. Science is a body of knowledge. It's a subject field that covers many things and numerous sub areas.
8 0
3 years ago
Read 2 more answers
The best rebounders in basketball have a vertical leap (that is, the vertical movement of a fixed point on their body) of about
nadya68 [22]

Answer:

a) 4.45 m/s

b) 0.9 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -9.81\times 1}\\\Rightarrow u=4.45\ m/s

a) The vertical speed when the player leaves the ground is 4.45 m/s

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-4.45}{-9.81}\\\Rightarrow t=0.45\ s

Time taken to reach the maximum height is 0.45 seconds

s=ut+\frac{1}{2}at^2\\\Rightarrow 1=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{1\times 2}{9.81}}\\\Rightarrow t=0.45\ s

Time taken to reach the ground from the maximum height is 0.45 seconds

b) Time the player stayed in the air is 0.45+0.45 = 0.9 seconds

6 0
3 years ago
A 0.49-kg cord is stretched between two supports,7.3m apart. When one support is struck by a hammer, a transverse wave travels d
Wewaii [24]

Answer:

T= 5.18N

Explanation:

u = mass of chord / length of chord

u = 0.49/ 7.3

u = 0.067 kg/m

Velocity of sound waves (v) =length of chord / time taken for wave to travel

v = 7.3 / 0.83 = 8.795m/s

Tension is calculated below using the formula

T = v² * u

T = (8.795)² x 0.067

T= 5.18N

3 0
3 years ago
Calculate the amount of heat (kcal) released when 50.0g of steam at 100*c hits the skin, condenses, and cools to a body temperat
luda_lava [24]
As the steam touches the skin, it undergoes a phase change and releases latent heat due to the phase change. As it reaches equilibrium, it releases sensible heat. We calculate as follows:

Q = latent heat + sensible Heat
Q = 2.26 kJ / g (50.0 g) + 50.0 g ( 4.18 J / g C) (37 C - 100 C) ( 1 kJ / 1000 J)
Q = 99.833 kJ
6 0
3 years ago
Read 2 more answers
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