Answer:
78.96 g of NaC2H3O2
Explanation:
We are given;
- Volume of the solution as 350 mL
- Molarity of the solution as 2.75 M
- Molar mass of the solute NaC2H3O2 as 82.04 g/mol
We are required to determine the mass of the solute;
First we determine the number of moles;
Moles = Molarity × Volume
Therefore;
Moles of the solute = 2.75 M × 0.350 L
= 0.9625 moles
Second, we determine the mass
Mass = Moles × Molar mass
= 0.9625 moles × 82.04 g/mol
= 78.9635 g
= 78.96 g
Therefore, the mass of NaC2H3O2 needed is 78.96 g
Answer:
0.287 M
Explanation:
Multiply the concentration of each solution by the volume of each (in liters) to get the moles of NaOH in that solution.
0.15 M • 5.4000 L = 0.81 mol NaOH
4.0 M • 0.2012 L = 0.80 mol NaOH
Add the mol of NaOH together to get the total --> 0.81 + 0.80 = 1.61 mol NaOH
Divide by the total volume of solution (5400.0 mL + 201.2 mL = 5,601.2 mL = 5.6012 L)
1.61 mol / 5.6012 L = 0.287 M NaOH
Answer:
Cr(OH)2(s), Na+(aq), and NO3−(aq)
Explanation:
Let is consider the molecular equation;
2NaOH(aq) + Cr(NO3)2(aq) -----> 2NaNO3(aq) + Cr(OH)2(s)
This is a double displacement or double replacement reaction. The reacting species exchange their partners. We can see here that both the sodium ion and chromium II ion both exchanged partners and picked up each others partners in the product.
Sodium ions and nitrate ions now remain in the solution while chromium II hydroxide which is insoluble is precipitated out of the solution as a solid hence the answer.
pH. 10 because it is strong base
I can't remember any of the weights of the individual elements but here is how you solve it:
Molecular weight of copper + nitrogen + 3 oxygens = molecular weight of the compound.
M = moles / liter
.350 moles / 1 liter
Do .350 moles / liter x the molecular weight (g / mole) of the compound = the answer in g / L
