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4 years ago

To determine a waves' frequency, you must know the

Physics

2 answers:

kykrilka [37]4 years ago

7 0

B. number of oscillations in a given period of time.

Lena [83]4 years ago

7 0

Answer : Frequency equals number of oscillations in a given period of time.

Explanation :

The number of oscillations in a given period of time is known as the frequency of the wave. It is denoted by $\nu$ . Its SI unit is hertz (Hz).

It is also defined as the inverse of time period i.e.

$\nu=\dfrac{1}{T}$

T is the time period.

Hence, the correct option is (B) " number of oscillations in a given period of time ".

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When the valve between the 2.00-L bulb, in which the gas pressure is 2.00 atm, and the 3.00-L bulb, in which the gas pressure is

padilas [110]

Answer:

$P_{C} = 3.2\, atm$

Explanation:

Let assume that gases inside bulbs behave as an ideal gas and have the same temperature. Then, conditions of gases before and after valve opened are now modelled:

Bulb A (2 L, 2 atm) - Before opening:

$P_{A} \cdot V_{A} = n_{A} \cdot R_{u} \cdot T$

Bulb B (3 L, 4 atm) - Before opening:

$P_{B} \cdot V_{B} = n_{B} \cdot R_{u} \cdot T$

Bulbs A & B (5 L) - After opening:

$P_{C} \cdot (V_{A} + V_{B}) = (n_{A} + n_{B})\cdot R_{u} \cdot T$

After some algebraic manipulation, a formula for final pressure is derived:

$P_{C} = \frac{P_{A}\cdot V_{A} + P_{B}\cdot V_{B}}{V_{A}+V_{B}}$

And final pressure is obtained:

$P_{C} = \frac{(2\,atm)\cdot (2\,L)+(4\,atm)\cdot(3\,L)}{5\,L}$

$P_{C} = 3.2\, atm$

5 0

3 years ago

Water at 20 C flows through a 5-cm-diameter pipe that has a 180 vertical bend, as in Fig. P3.43. The total length of pipe betwee

Nataliya [291]

Answer:

F = 749 [N]

Explanation:

We must give full information on this problem, as well as the question that needs to be resolved.

Water at 20°C flows through a 5-cm-diameter pipe that has a 180° vertical bend. The total length of pipe between flanges 1 and 2 is 75 cm. When the weight flow rate is 230 N/s,

P1=165kPa

and

P2=134kPa

Neglecting pipe weight, determine the total force that the flanges must withstand for this flow.

We must make a U-shaped body diagram of the pipe in order to visualize the forces acting according to the pressures and the area of the pipe.

Then by means of the second law of motion of Newton, which says that the sum of the forces must be equal to the product of mass times acceleration, we can find the force Fp

Let us remember that pressure is defined as the divided force over the area, therefore:

F = P *A

where:

P = pressure

A = area

The product of the mass by acceleration, is equal to the product of the speed of the fluid by the mass flow, since we know the weight of the fluid we can find its mass flow.

$W_{flow}=230[N/s]\\W_{flow} =g*m_{flow}\\m_{flow} = W_{flow} / g\\m_{flow} = 230/9.81\\m_{flow}= 23.45[kg/s]$

In the function of the mass flow, we can find the velocity of the fluid, as we also know the diameter of the pipe

$m_{flow} = density*v*A\\where\\density = 1000[kg/m^{3}]\\ v= velocity[m/s]\\A = area [m^{2}]\\v=\frac{m_{flow}}{density*A} \\v=\frac{23.45}{1000*\frac{\pi}{4}*(5*10^{-2})^{2} } \\v= 11.94 [m/s]$

We know that the atmospheric pressure is equal to:

$P_{atm} = 101.325[kpa]$

The value of the pipe area is calculated for a circular section

$A = \frac{\pi}{4} * (0.05)^{2}\\ A = 0.00196[m^{2} ]$

The resultant force is 749 [N]

The solution of the equations and the free body diagram can be seen in the attached picture.

3 0

3 years ago

Question 36 pls<br> Physics

Lera25 [3.4K]

$R=\frac{U}{I}=\frac{0.5V}{180\cdot10^{-6}A}\approx2.78k\Omega$

7 0

3 years ago

Can any one give me examples of cadmium and Zinc together?

gayaneshka [121]

Cadmium zinc telluride, zinc cadmium sulfide

7 0

3 years ago

If the car were being moved sideways, could you determine the force on the car by using the weight equation

VashaNatasha [74]

No, if the car were moving sideways, then the forces used would be on the horizontal axis. So the weight equation would be extraneous, unless one is determining the net force through an inclined plane

7 0

3 years ago