<span>Examples of genetically engineered (transgenic) organisms currently on the market include plants with resistance to some insects, plants that can tolerate herbicides, and crops with modified oil content.</span>
A.) is chemical, B.) is physical, C.) is physical, D.) is chemical, E.) is physical, F.) is physical, G.) is physical, and H.) is chemical.
Answer:
V = 308.1 m/s θ = -64º
Explanation:
a and b) We will use the projectile launch equations where we are asked to find the speed when the tank reaches the ground
Let's start by breaking down the speed
Vox = Vo cos θ
Voy = Vo sint θ
Vox = 140 cos 15 = 135.2 m / s
Voy = 140 sin 15 = 36.2 m / s
Let's look for vertical speed when it hits the ground
Vy² = Voy² - 2gy
Vy = √(36.2² - 2 9.8 3.98 103) = √ (1310-78008)
Vy = 276.9 m / s
We have both components.
V² = Vx² + Vy²
V = √ (135.2² + 276.9²)
V = 308.1 m / s
tan θ = Vy / Vx
tan θ = -276.9 / 135.2 = 2,048
θ = -64º
The negative sign means that it is measured from the x-axis clockwise
c and d) We repeat the same calculation for tank B, the only difference is the angle T = -15º
Vox = 140 cos (-15)
Voy = 140 sin (-15)
Vox = 135.2 m / s
Voy = 140 sin (-15)
Voy = -36.2 m / s
We calculate the vertical speed
Vy² = Voy² - 2 g Y
Vy = √ ((-36.2)² - 2 9.8 3980)
Vy = 276.9 m / s
V = √(135.3²2 + 276.9²)
V = 308.1 m/s
tan θ = -276.9 / 135.2
θ = -64
You can see that the speeds and angles are the same in both cases, the difference between these two situations is in the horizontal distance that runs each story
Answer:
0.6375 m/s
Explanation:
Let x be the distance of the man from the building
from the figure attached
initially the value of x=12
Given:
![\frac{dx}{dt}=-1.7m/s](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%7D%7Bdt%7D%3D-1.7m%2Fs)
where the negative sign depicts that the distance of the man from the building is decreasing.
Now, Let The length of the shadow be = y
we have to calculate
when x=4
from the similar triangles
we have,
or
![y=\frac{24}{12-x}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B24%7D%7B12-x%7D)
Differentiating with respect to time 't' we get
![\frac{dy}{dt}=-\frac{24}{12-x}^2\frac{-dx}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdt%7D%3D-%5Cfrac%7B24%7D%7B12-x%7D%5E2%5Cfrac%7B-dx%7D%7Bdt%7D)
or
![\frac{dy}{dt}=\frac{24}{12-x}^2\frac{dx}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdt%7D%3D%5Cfrac%7B24%7D%7B12-x%7D%5E2%5Cfrac%7Bdx%7D%7Bdt%7D)
Now for x = 4, and
we have,
![\frac{dy}{dt}=\frac{24}{12-4}^2\times (-1.7)](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdt%7D%3D%5Cfrac%7B24%7D%7B12-4%7D%5E2%5Ctimes%20%28-1.7%29)
or
![\frac{dy}{dt}=-0.6375m/s](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdt%7D%3D-0.6375m%2Fs)
<u>here, the negative sign depicts the decrease in length and in the question it is asked the decreasing rate thus, the answer is </u><u>0.6375m/s</u>