Reaction of dissociation: Ag₂SO₄ → 2Ag⁺ + SO₄²⁻.
m(Ag₂SO₄) = 4 g.
V(Ag₂SO₄) = 1 l.
n(Ag₂SO₄) = m(Ag₂SO₄) ÷ M(Ag₂SO₄).
n(Ag₂SO₄) = 4 g ÷ 311,8 g/mol.
n(Ag₂SO₄) = 0,0128 mol.
n(Ag⁺) = 2 · 0,0128 mol = 0,0256 mol.
n(Ag₂SO₄) = n(SO₄²⁻) = 0,0128 mol.
c(Ag⁺) = n ÷ V = 0,0256 mol ÷ 1 l = 0,0256 mol/l.
Ksp = c(Ag⁺)² · c(SO₄²⁻).
Ksp = (0,0256 mol/l)² · 0,0128 mol/l.
Ksp = 8,3·10⁻⁶.
Answer:
V= 48L
Explanation:
Moles of N2 = m/M = 30/28= 1.07moles
From the equation of reaction
N2 +3H2 → 2NH3
1mole of N2 produces 2mole of NH3
Hence
1.07moles will produce 1.07×2= 2.14 moles
At STP, 1mole occupy 22.4L
Hence volume of N2 produced = 2.14×22.4= 48 L
Answer:
F G there you go the guy on top is right
Explanation:
F G
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