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tangare [24]
3 years ago
14

A support crossbeam on a high speed train is made from a titanium rod that has a length of 0.650m when measured by an observer o

n the train. The beam is positioned such that the observer on the train measures an angle of 39degrees between the crossbeam and the floor of the train. (Figure 1) At what speed u would the train have to be traveling in order for an observer standing outside the train to measure the angle as 83degrees ? In the figure, S indicates the reference frame of the observer standing outside the train and S' indicates the reference frame of the observer on the train.
The beam has two dimensions: a height that is perpendicular to the floor of the train and a width that is parallel to the floor of the train. The angle between the beam and the floor appears different as measured by observers on the moving train and on the platform for which of the following reasons?

A. The crossbeam is moving relative to the observer on the platform so the height appears contracted.
B. The crossbeam is moving relative to the observer on the platform so the width appears contracted.
C. The crossbeam is moving relative to the observer on the train so the width appears contracted.
D. The crossbeam is moving relative to the observer on the train so the height appears contracted.
Physics
1 answer:
Vilka [71]3 years ago
3 0

Answer:

A) The crossbeam is moving relative to the observer on the platform so the height appears contracted.

Explanation:

The observer on the train and the beam are in the same reference frame. That means observer on the train will measure the proper length of the beam not the contracted length . the observer is outside and the plank is in the moving system,it will appear to be moving.

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Answer:

See explanation below

Explanation:

In this case, you want to know if you put an object between these forces, which direction would go.

To know this, we need to calculate the moment of an object, which is defined as the product of a force and it's distance. In other words:

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And, in order to reach equilibrium the force will exert a direction in clockwise or anticlosewise, and these moments, should be even:

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The clockwise would be the forces to the right, and anticlock would the only force to the left of the axle.

Clockwise moment = (10 * 0.8) + (25 * 2.6) = 73 Ns

Anticlockwise moment = 34 * 3.5 = 119 Ns.

As we can see, the moment in the anticlockwise is higher than the actual clockwise moment, therefore, we can assume that the object will move anticlockwise, or simply move to the left.

Hope this helps

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