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MakcuM [25]
3 years ago
12

Calculate the mass of O2 produced if 3.450 g potassium chlorate is completely decomposed by heating in presence of a catalyst (m

anganese dioxide)
Chemistry
1 answer:
sergiy2304 [10]3 years ago
3 0

The reaction is:

2 KClO3(s) → 3 O2(g) + 2 KCl(s) <span>

<span>A catalyst simply lowers the activation energy so MnO2 is not part of the overall reaction.

By stoichiometry: 

<span>3.45 g KClO3 x 1 mol/ 122.55g KClO3 x 3 mol O2/ 2 mol KClO3 x 31.99g/ 1 mol O2 = 331.096/ 245.1 = 1.35 grams O2 produced 

Answer:
1.35 grams O2</span></span></span>
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A scientist measures the speed of sound in a monatomic gas to be 449 m/s at 20∘C. What is the molar mass of this gas?
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Answer:

The molar mass of the gas is 36.25 g/mol.

Explanation:

  • To solve this problem, we can use the mathematical relation:

ν = \sqrt{3RT/M}

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T is the temperature of the gas in Kelvin <em>(T = 20 °C + 273 = 293 K)</em>,

M is the molar mass of the gas in <em>(Kg/mol)</em>.

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<em>by squaring the two sides:</em>

(449 m/s)² = (3 (8.314 J/mol.K) (293 K)) / M,

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<em>∴ The molar mass of the gas is 36.25 g/mol.</em>


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