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2 years ago

Light travels at 3. 0 × 108 m/s in a vacuum and slows to 2. 0 × 108 m/s in glass. What is the index of refraction of glass?.

Physics

1 answer:

Sergio039 [100]2 years ago

5 0

The required value of the index of refraction of glass is 1.5.

Given data:

The speed of light in a vacuum is, $c = 3.0 \times 10^{8} \;\rm m/s$ .

The speed of light in a glass is, $v = 2.0 \times 10^{8} \;\rm m/s$ .

Light has the tendency to travel from one medium to another, then the difference between the speeds of light in various mediums is determined by a term, known as the index of refraction. The mathematical expression for the index of refraction of glass is,

n = c / v

Solving as

$n = \dfrac{3.0 \times 10^{8}}{2.0 \times 10^{8}}\\\\n = 1.5$

Thus, we can conclude that the required value of the index of refraction of glass is 1.5.

Learn more about the index of refraction here:

brainly.com/question/17156275

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3 years ago

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Ultraviolet, x-ray, gamma ray

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Electromagnetism radiation are waves of energy that is expressed by the Planck relationship

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2 years ago

How much must a woman weigh ( force) if the pressure she exerts while standing on one foot has an area of 0.6m squared exerts a

lions [1.4K]

Answer:

W = 9.6 N

Explanation:

Given that,

Area on 1 foot, A = 0.6 m²

Pressure, P = 16 Pa

The pressure is given by force acting per unit area. So,

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3 years ago

a sphere of diameter 6•0cm is moulded into a thin uniform wire of diameter 0•2mm.calculate the length of the wire in metres

Scilla [17]

The length of the wire is 36 m.

<u>Explanation:</u>

Given, Diameter of sphere = 6 cm

We know that, radius can be found by taking the half in the diameter value. So,

$\text { sphere radius, } R=\frac{D}{2}=\frac{6}{2}=3 \mathrm{cm}=3 \times 10^{-2} \mathrm{m}$

Similarly,

$\text { wire radius, } r=\frac{0.2}{2}=0.1 \mathrm{mm}=1 \times 10^{-3} \mathrm{m}$

We know the below formulas,

$\text {volume of sphere}=\frac{4}{3} \times \pi \times R^{3}$

$\text {volume of wire}=\pi \times r^{2} \times l$

When equating both the equations, we can find length of wire as below, where $\pi=\frac{22}{7}$

$\frac{4}{3} \times \pi \times R^{3}=\pi \times r^{2} \times l$

$\frac{4}{3} \times \frac{22}{7} \times\left(3 \times 10^{-2}\right)^{3}=\frac{22}{7} \times\left(1 \times 10^{-3}\right)^{2} \times l$

The $\pi$ value gets cancelled as common on both sides, we get

$\frac{4}{3} \times 27 \times 10^{-6}=10^{-6} \times l$

The $10^{-6}$ value gets cancelled as common on both sides, we get

$l=4 \times 9=36 m$

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3 years ago