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Anton [14]
3 years ago
13

Follow the path of the current leaving the battery and returning back to the battery through two light bulbs if they are a) conn

ected in series and b) connected in parallel. Please explain these are all the points i have left
Physics
2 answers:
miskamm [114]3 years ago
7 0
Well there's only one path for the current to travel through in a series circuit.
there are multiple paths in a parallel circuit.    
OleMash [197]3 years ago
6 0

Answer:

If we have only one path, this means that the circuit is connected in series, one light bulb after the other, the current decreases a bit of intensity when it passes through the first light bulb and reaches the other with less intensity, so in this case, you may see that the first one brights more intensely than the second one, if there is a remanent of current, it goes again to the battery. In the parallel case, we have a bifurcation of the path, where the current divides into both paths and each part goes to a single light bulb, here we will see both light bulbs shine with the same intensity.

so the paths are:

Series:

battery----light bulb--- light bulb---battery

Parallel:

               light bulb

battery---<                 >-------battery

                light bulb

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shusha [124]

Answer:

17.3 m

Explanation:

Given that,

Mass of a hammer is 0.58 kg

Velocity with which the hammer slides is 6.69 m/s at constant speed.

The roof makes an angle of 18 ◦ with the horizontal, and its lowest point is 18.2 m from the ground. We need to find the horizontal distance traveled by the hammer between the time is leaves the roof of the house and the time it hits the ground. Firstly, we will find the time taken by the hammer when it reaches ground in vertical direction.

y=y_0+v_ot +\dfrac{1}{2}gt^2

Putting all the values,

0=18.2+6.69t-\dfrac{1}{2}\times 9.8t^2\\\\-4.9t^2+6.69t+18.2=0\\\\t=\dfrac{-6.69+\sqrt{6.69^{2}-4\cdot-4.9\cdot18.2}}{2\cdot-4.9}, \dfrac{-6.69-\sqrt{6.69^{2}-4\cdot-4.9\cdot18.2}}{2\cdot-4.9}\\\\t=-1.36\ s\ \text{and}\ t=2.72\ s

Neglecting negative value,

To find horizontal distance, multiply 2.72 s with the horizontal component of velocity.

d=2.72\times 6.69\times \cos(18)\\\\d=17.3\ m

3 0
3 years ago
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If you ran 15 km/h for 20 min, how much distance would you cover?
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Since we have 15 kilometers per hour, and we're looking for 20 minutes, let's set up proportions.
20/60 minutes = x/15
20/60 = 1/3, so let's leave that simplified.
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By using an electric field, it is feasible to differentiate between these different forms of radiation.

<h3>What is a radioactive source?</h3>

A source that emits radiation like gamma, beta, and alpha rays is said to be radioactive. Using an electric field, we can discriminate between these different forms of radiation.

The field does not deflate the gamma rays, but it does deflate the alpha and beta rays, with the alpha being deflated to the field's negative portion and the beta to its positive part.

Hence, by using an electric field, it is feasible to differentiate between these different forms of radiation.

To learn more about the radioactive source refer;

brainly.com/question/12741761

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