I need help i need the response

During a clothing store's Bargin Days, the regular price for T-shirts is discounted to $8.25. You have an additional coupon for

kakasveta [241]

Answer:

$p(t) = 8.25t - 5$

b) The cost of 11 T-shirts during bargain days is $85.75

Step-by-step explanation:

We are given the following information in the question:

Discounted cost of one T-shirt = $8.25

Additional off on coupon = $5.00

Let t be the number of T-shirts bought during the bargain days.

a) Then, the price of t T-shirts with the discount applied will be given by the function:

$p(t) = \text{Number of T-shirts}\times \text{Discounted price for 1 T-shirt} - \text{Coupon Off}\\p(t) = 8.25t - 5$

b) Price during Bargain Days for 11 shirts

We put t = 11 in the above function:

$p(t) = 8.25t - 5\\p(11) = 8.25(11) - 5 = 85.75$

Thus, the cost of 11 T-shirts during bargain days is $85.75

4 0

3 years ago

to which family does the function y=(x 2)1/2 3 belong? a: quadratic b: square root c: exponential d :reciprocal

Neko [114]

Answer:

option a is correct.

Step-by-step explanation:

We have given the equation:

$y=x+\frac{1}{2}^{\frac{1}{2}}+3$

Squaring both sides of the above equation we get:

$y^2=(x+\frac{1}{2})^2+9+2\cdot(x+\frac{1}{2})(3)$

After simplifying the first step

$y^2=x^2+\frac{1}{4}+x+9+3(2x+1)$

$y^2=x^2+x+6x+3+9+\frac{1}{4}$

$y^2=x^2+7x+12+\frac{1}{4}$

After final simplification we get:

$4y^2=4x^2+28x+49$

We are getting quadratic equation since, the degree in resultant is 2.

Therefore, option a is correct.

8 0

3 years ago

Read 2 more answers

A waitress earned $7 per hour at her job plus an additional $50 in tips on Friday. She earned more than $99 total. Which inequal

aivan3 [116]

Answer:

Step-by-step explanation:

7h + 50= 99

99-50 =49

7h=49

49/7

h=7

here's the steps i don't know which part you need

5 0

3 years ago

9 less than a number equals the product of 2 and 4

yarga [219]

X - 9 = 8
x - 9 +9 = 8 +9

x = 17

x = 17

5 0

3 years ago

Read 2 more answers

According to a survey, 60 % of the residents of a city oppose a downtown casino. Of these 60 % about 8 out of 10 strongly opp

katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

Step-by-step explanation:

(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino.

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

Probability that a radomly selected resident opposes the casino: P(A)

Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the probability that a radomly selected resident opposes the casino, P(A)

Probability = number of favorable outcomes / number of possible outcomes

P(A) is given as 60%, which in decimal form is 0.60

ii) Next, determine,the probability that a resident who opposes the casino strongly opposes it, P(B/A):

It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or intersection: P(A∩B).

So, you can use the definition of conditional probability:

P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

P(A∩B) = P(B/A)×P(A) = (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that a radomly selected resident who opposes the casino does strongly oppose the casino, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

8 0

3 years ago