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Elza [17]
3 years ago
15

You are on a school bus driving north at 20 m/s. You walk toward the back of the bus with a velocity of 6 m/s. What is your velo

city relative to the road?
A. 6 m/s south
B. 14 m/s north
C. 20 m/s north
D. 26 m/s north
Physics
1 answer:
Ganezh [65]3 years ago
3 0
I answered the question but it got deleted?? why?
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Two tractors pull against a 1000 kg log. If the angle of the tractors' chains in relation to each other is 18.0° (each 9.0° from
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Pie ?????????????? π pizza ??? wut
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The light bulb converts electrical energy into light and ____. A) chemical B) electromagnetic C) heat D) nuclear
morpeh [17]
The light bulb converts electrical energy into light and heat. 


Good luck! (:
7 0
2 years ago
Read 2 more answers
What is the mass of a man who accelerates 4 m/s2 under the action of a 200 N net force?
Over [174]

Answer:

\huge  \boxed{ \boxed{50 \:   kg }}

Explanation:

The mass of the man can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{200}{4}  \\

We have the final answer as

<h3>50 kg</h3>

Hope this helps you

7 0
2 years ago
A 1.2 nf parallel-plate capacitor has an air gap between its plates. Its capacitance increases by 3.0 nf when the gap is filled
Damm [24]

Answer:

2.5

Explanation:

The capacitance of a parallel-plate capacitor filled with dielectric is given by

C=kC_0

where

k is the dielectric constant

C_0 is the capacitance of the capacitor without dielectric

In this problem,

C_0=1.2 nF is the capacitance of the capacitor in air

C=3.0 nF is the capacitance with the dielectric inserted

Solving the equation for k, we find

k=\frac{C}{C_0}=\frac{3.0 nF}{1.2 nF}=2.5

3 0
3 years ago
Read 2 more answers
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9.0 km/h due east. Runner B is initia
Eduardwww [97]

Answer:

From the data we know that runner A and runner B are 11 km apart from the start because (6+5) km

So the runner from the east direction has distance as unknown km, rate= 9 k/h ; time= d/r=x/9 hr

So runner towards the west will be

distance = 11-x, rate= 8 k/h, time = d/r = (11-x)/8

So equating east and west time we have

x/9= (11-x)/8

8x=99-9x

17x=99

x=5.92 km

That is the distance covered by runner towards the east and he will meet the runner toward the west at

6-5.92=0.08 km west of the flagpole.

7 0
3 years ago
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