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ICE Princess25 [194]
3 years ago
15

Nathan accelerates his skateboard uniformly along a straight path from rest to 12.5 m/s in 2.5 s.

Physics
1 answer:
kicyunya [14]3 years ago
5 0

Answer:

<h2>a) Nathan's acceleration is 5 m/s² </h2><h2>b) Nathan's displacement during this time interval is 15.625 m</h2><h2>c) Nathan's average velocity during this time interval is 6.25 m/s</h2>

Explanation:

a) We have equation of motion v = u + at

     Initial velocity, u = 0 m/s

     Final velocity, v = 12.5 m/s    

     Time, t = 2.5 s

     Substituting

                      v = u + at  

                      1.25 = 0 + a x 2.5

                      a = 5 m/s²

     Nathan's acceleration is 5 m/s²

b) We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

        Acceleration, a = 5 m/s²  

        Time, t = 2.5 s      

     Substituting

                      s = ut + 0.5 at²

                      s = 0 x 2.5 + 0.5 x 5 x 2.5²

                      s = 15.625 m

      Nathan's displacement during this time interval is 15.625 m

c) Displacement = 15.625 m

   Time = 2.5 s

  We have

           Displacement = Time x Average velocity

           15.625 = 2.5 x  Average velocity

           Average velocity = 6.25 m/s

     Nathan's average velocity during this time interval is 6.25 m/s

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