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12345 [234]
3 years ago
10

What are the three main categories of elements?

Physics
2 answers:
o-na [289]3 years ago
8 0

Answer:

Classification of the Elements. These three groups are: metals, nonmetals, and inert gases.

Explanation:

iogann1982 [59]3 years ago
7 0

Answer:If you're referring to Organic Molecules, then they are CARBON, HYDROGEN and OXYGEN.

Explanation:

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A sky diver, with parachute unopened, falls 625 m in 15.0 s. Then she opens her parachute and falls another 362 m in 139 s. What
Jobisdone [24]

Answer:

v_{avg} = 6.41 m/s

Explanation:

Average velocity is defined as the ratio of total displacement of the motion and total time taken in that motion

here we know that initially the sky diver drops without opening parachute by total displacement 625 m

then she open her parachute and drop another 362 m

so first it took time t = 15 s to drop without open parachute

then it took t = 139 s to drop next displacement

so here total displacement is given as

d = 625 m + 362 m

total time is given as

t = 15 s + 139 s

so average velocity is given as

v_{avg} = \frac{625 + 362}{15 + 139}

v_{avg} = 6.41 m/s

4 0
3 years ago
A hollow conductor is positively charged. Asmall uncharged metal ball is lowered by a silk thread through asmall opening in the
dimulka [17.4K]

Answer:

Explanation:

According to the property of a conductor, the entire charge will reside on the outer surface of the conductor, there is no charge on the inner side of the conductor. As the uncharged metal ball touches the inner surface of the conductor, it does not attain any charge as the inner side of the conductor has no charge.

So option (c) is correct.

8 0
3 years ago
A hockey puck with a mass of 0.159 kg slides over the ice. The puck initially slides with a speed of 4.75 m/s, but it comes to a
Anton [14]

Answer:

The energy dissipated as the puck slides over the rough patch is 1.355 J

Explanation:

Given;

mass of the hockey puck, m = 0.159 kg

initial speed of the puck, u = 4.75 m/s

final speed of the puck, v = 2.35 m/s

The energy dissipated as the puck slides over the rough patch is given by;

ΔE = ¹/₂m(v² - u²)

ΔE = ¹/₂ x 0.159 (2.35² - 4.75²)

ΔE = -1.355 J

the lost energy is 1.355 J

Therefore, the energy dissipated as the puck slides over the rough patch is 1.355 J

5 0
3 years ago
Which planet was almost massive enough to have become a star?
ololo11 [35]
Jupiter ............................................
3 0
2 years ago
Read 2 more answers
A 2.8-kg cart is rolling along a frictionless, horizontal track towards a 1.2-kg cart that is held initially at rest. The carts
agasfer [191]

Answer with Explanation:

We are given that

Mass of one cart,m_1=2.8 kg

Mass of second cart,m_2=1.2 kg

Initial velocity of one cart,u_1=4.6m/s

Initial velocity of second cart,u_2=-2.7 m/s

a.Total momentum,P=m_1u_1+m_2u_2=2.8(4.6)+1.2(-2.7)

P=9.64 kgm/s

b.Velocity of second cart,v_2=0

According to law of conservation of momentum

Initial momentum=Final momentum

9.64=2.8v_1+1.2\times 0

v_1=\frac{9.64}{2.8}

v_1=3.44m/s

8 0
3 years ago
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