Answer:
Explanation:
As we know that the pressure inside the liquid level is given as
here we have
h = 10.9 km
also we know that
now we have
A 2.8-kg cart is rolling along a frictionless, horizontal track towards a 1.2-kg cart that is held initially at rest. The carts
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You must throw the snow ball by velocity 9.43 m/s horizontally to
hit him
Explanation:
You throw the snow ball horizontally from a height 5.5 meters
Your favorite physics teacher is 10 m away from you
You hit him on the foot
1. The initial velocity of the ball is v
2. The vertical component of v is zero because you throw the ball
horizontally
3. The vertical distance h is 5.5 m
4. The horizontal distance x is 10 m
We need to find how fast you must throw the snow ball to hit him
→ h = t +
g t²
→ h = -5.5 m ⇒ height below the point of thrown
→ g = -9.8 m/s²
→ = 0 ⇒ vertical component of v
→ -5.5 = (0) t + (-9.8) t²
→ - 5.5 = -4.9 t²
Divide both sides by -4.9
→ t² = 1.12245
Take √ for both sides
→ t = 1.06 seconds
→ x = t
→ = v
→ x = 10 m , t = 1.06
→ 10 = v(1.06)
Divide both sides by 1.06
→ v = 9.43 m/s
You must throw the snow ball by velocity 9.43 m/s horizontally to
hit him
Learn more:
You can learn more about velocity in brainly.com/question/13103128
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