Answer:
you should provide the options for us to answer?
Before we could discuss this in any specific detail, I think we would have to
know the angles. A generic discussion without actual numbers for the angles
would be just plain too confusing.
The general approach is that the vertical components of both tensions
add up to 20N, and the horizontal components are equal but in opposite
directions. That's the only way that the mass is hanging motionless.
You have to find the horizontal and vertical components of the tensions
by using the angles and maybe the lengths of the ropes.
G/mL is equivalent to g/cm^3, so we first convert the dimensions into cm:
2.20 cm, 1.35 cm, and 1.25 cm
Then the total volume is: V = lwh = 3.7125 cm^3
To get the density, we divide mass by volume: 2.50 g / 3.7125 cm^3 = 0.6734 g/cm^3 = 0.6734 g/mL
The answer is a because tjhey do move at a molecular movemn
According to Newton's second law, the force applied to an object is equal to the product between the mass of the object and its acceleration:

where F is the magnitude of the force, m is the mass of the object and a its acceleration.
In this problem, the object is the insect, with mass

. The acceleration of the insect is

, therefore we can calculate the force exerted by the car on the insect:

How do we find the force exerted by the insect on the car?
According to Newton's third law (known as action-reaction law), when an object A exerts a force on an object B, object B also exerts a force equal and opposite on object A. Therefore, the force exerted by the insect on the car is equal to the force exerted by the car on the object, so it is 0.01 N.