The net torque exerted by the children on the branch of the tree is 1382 N-m.
The torque exert by the kids is calculated as
T= 45.6*9.8*1.28*cos27.5°+36*9.8*(2.25-1.28)cos27.5°
T=1382 N-m
Hence, The net torque exerted by the children on the branch of the tree is 1382 N-m.
Answer:
5.78amps
Explanation:
Given data
Time t= 57 seconds
Charge Q= 330C
Current I= ??
The expression for the electric current is given as
Q= It
Substituting we have
330= I*57
I= 330/57
I=5.78 amps
Hence the current is 5.78amps
Answer:
Explanation:
Given
inclination 
coefficient of kinetic friction 
As crate is moving Down therefore friction will oppose the motion
using FBD







Answer:
a) F_{e} - F_{m} = 0, b) v = 666.67 m / s
Explanation:
For the proton to move y-axis the sum of the electric and magnetic force must be zero, therefore
= 0
a) ∑ F = 0
F_{e} - F_{m} = 0
b) we write the forces
q E = q v B
v = E / B
Let's calculate
v = 300 / 0.45
v = 666.67 m / s