Can you answer this for me please

Find the average velocity of the following 4 velocity measurements:

andriy [413]

The average velocity of the following 4 velocity measurements will be d) 8.7 m/s

average of given velocities = sum of all velocities divided by number of velocity mentioned in the question

average velocity = ( v1 + v2 + v3 + v4 ) / 4

= ( 9.6 + 8.8 + 7.6 + 8.7 ) / 4 = 8.675 ≈ 8.7 m/s

correct answer d)

The average velocity of the following 4 velocity measurements will be d) 8.7 m/s

To learn more about velocity here :

brainly.com/question/18084516

#SPJ1

4 0

1 year ago

An is_____ produced around a wire when electrical current is in the wire

svlad2 [7]

<span>A magnetic field is produced around a wire when electrical current is in the wire :)</span>

3 0

3 years ago

Piano tuners tune pianos by listening to the beats between the harmonics of two different strings. When properly tuned, the note

Sophie [7]

(a) 2 Hz

The frequency of the nth-harmonic is given by

$f_n = n f_1$

where

$f_1$ is the fundamental frequency

Therefore, the frequency of the third harmonic of the A ( $f_1 = 440 Hz$ ) is

$f_3 = 3 \cdot f_1 = 3 \cdot 440 Hz =1320 Hz$

while the frequency of the second harmonic of the E ( $f_1 = 659 Hz$ ) is

$f_2 = 2 \cdot f_1 = 2 \cdot 659 Hz =1318 Hz$

So the frequency difference is

$\Delta f = 1320 Hz - 1318 Hz = 2 Hz$

(b) 2 Hz

The beat frequency between two harmonics of different frequencies f, f' is given by

$f_B = |f'-f|$

In this case, when the strings are properly tuned, we have

- Frequency of the 3rd harmonic of A-note: 1320 Hz

- Frequency of the 2nd harmonic of E-note: 1318 Hz

So, the beat frequency should be (if the strings are properly tuned)

$f_B = |1320 Hz - 1318 Hz|=2 Hz$

(c) 1324 Hz

The fundamental frequency on a string is proportional to the square root of the tension in the string:

$f_1 \propto \sqrt{T}$

this means that by tightening the string (increasing the tension), will increase the fundamental frequency also*, and therefore will increase also the frequency of the 2nd harmonic.

In this situation, the beat frequency is 4 Hz (four beats per second):

$f_B = 4 Hz$

And since the beat frequency is equal to the absolute value of the difference between the 3rd harmonic of the A-note and the 2nd harmonic of the E-note,

$f_B = |f_3-f_2|$

and $f_3 = 1320 Hz$ , we have two possible solutions for $f_2$ :

$f_2 = f_3 - f_B = 1320 Hz - 4 Hz = 1316 Hz\\f_2 = f_3 + f_B = 1320 Hz + 4 Hz = 1324 Hz$

However, we said that increasing the tension will increase also the frequency of the harmonics (*), therefore the correct frequency in this case will be

1324 Hz

8 0

2 years ago

When I hurricane nearest land what causes the most damage

Svetllana [295]

Hey there!

When a hurricane is near land the wind and rain cause the most damage.

Hope it helped!

4 0

2 years ago

Read 2 more answers

Two bricks are released at the same time from the same point ten feet above the ground. One of the bricks is falling straight do

natita [175]

Both bricks will hit the ground at the same time.

Falling vertically is always accelerating at 9.8 m/s² because of gravity.
Nothing that's happening horizontally has any effect on that.
The brick that happens to have some horizontal motion will
probably hit the ground way over there, but that will still be
at the same TIME as this one.

This is a perfect place to remind you of the old unbelievable story,
which I'll bet you heard before:

If you fire a bullet horizontally from a gun, and at the exact same
moment you DROP another bullet out of your hand next to the gun,
the two bullets will hit the ground at the same time ! Even though
they'll be far apart.

Horizontal speed has no effect on vertical behavior.

7 0

2 years ago