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Sonja [21]
3 years ago
8

10 turns of wire are closely wound around a pencil as shown in the figure. when measured using a scale as shown, the length of t

otal turns is obtained 25mm. then a) What is the thickness of the wire? b) Express the thickness of the wire in centimetre.
Physics
1 answer:
agasfer [191]3 years ago
3 0

Answer:

1. 2.5 mm

2. 0.25 cm

Explanation:

Since the length of the 10 turns of the wire around the pencil is 25 mm, then;

1. the thickness of the wire = \frac{length of total turns}{number of turns}

                                         = \frac{25}{10}

                                        = 2.5 mm

The thickness of the wire is 2.5 mm.

2. Since 10 mm = 1 cm, then;

25 mm = 2.5 cm

So that,

the thickness of the wire in centimetre = \frac{length of total turns}{number of turns}

                                         = \frac{2.5}{10}

                                         = 0.25 cm

The thickness of the wire is 0.25 cm.

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Identify the physical mechanism that causes turbulent thermal conductivity.
myrzilka [38]

Answer:

Option A is correct.

Eddies due to enhanced mixing of fluid

Explanation:

Turbulent thermal conductivity is thermal conductivity that arises from the turbulent flow of fluids. It comes into play when a particukar fluid moves into turbulent regiom of flow where flow is no longer orderly and streamlines aren't discernable with the fluid layers all warping into one another forming vortices.

It is represented as K and is shown mathematically through the heat flux at turbulent flow

q = vCρT' = - K (∂T/∂y)

where

K = turbulent thermal conductivity

T' = the eddy temperature relative to the mean value,

C = Heat capacity the fluid

q = the rate of thermal energy transport by turbulent eddies.

The physical mechanism that cause turbulent thermal conductivity are similar to the causes of turbulent flow of fluids.

This includes sharp changes in fluid pressure and velocity of flow which is evident in eddies that come about in the enhanced mixing of fluids.

Hope this Helps!!!

5 0
3 years ago
What is the golden rule of lightning safety? (A.Don't stand under trees). (B.Avoid using electronics,)(C.Stay avvay from open sp
IrinaK [193]
The answer is d (head for cover)
6 0
3 years ago
What is the slit spacing of a diffraction necessary for a 600 nm light to have a first order principal maximum at 25.0°?
Sauron [17]

Explanation:

Given that,

Wavelength of light, \lambda=600\ nm=6\times 10^{-7}\ m

Angle, \theta=25^{\circ}

We need to find the slit spacing for diffraction. For a diffraction, the first order principal maximum is given by :

d\sin\theta=n\lambda

n is 1 here

d is slit spacing

d=\dfrac{\lambda}{\sin\theta}\\\\d=\dfrac{6\times 10^{-7}}{\sin(25)}\\\\d=1.41\times 10^{-6}\ m\\\\d=1.41\ \mu m

So, the slit spacing is 1.41\ \mu m.

6 0
3 years ago
Type the correct answer in the box. use numerals instead of words. anne has a sample of a substance. its volume is 20 cm3, and i
CaHeK987 [17]

The density of sample is 5 g/cm3

Given:

volume of sample = 20 cm3

mass of sample = 100 grams

To Find:

density of sample

Solution: Density is the measure of how much “stuff” is in a given amount of space. For example, a block of the heavier element lead (Pb) will be denser than the softer, lighter element gold (Au). A block of Styrofoam is less dense than a brick. It is defined as mass per unit volume

density = mass/volume

d = 100/20

d = 5 g/cm3

So, density of sample is 5 g/cm3

Learn more about Density here:

brainly.com/question/1354972

#SPJ4

6 0
1 year ago
The electric field in a region of space increases from 0 to 2150 N/C in 5.00 s. What is the magnitude of the induced magnetic fi
Feliz [49]

To solve this problem we will use the Ampere-Maxwell law, which   describes the magnetic fields that result from a transmitter wire or loop in electromagnetic surveys. According to Ampere-Maxwell law:

\oint \vec{B}\vec{dl} = \mu_0 \epsilon_0 \frac{d\Phi_E}{dt}

Where,

B= Magnetic Field

l = length

\mu_0 = Vacuum permeability

\epsilon_0 = Vacuum permittivity

Since the change in length (dl) by which the magnetic field moves is equivalent to the perimeter of the circumference and that the electric flow is the rate of change of the electric field by the area, we have to

B(2\pi r) = \mu_0 \epsilon_0 \frac{d(EA)}{dt}

Recall that the speed of light is equivalent to

c^2 = \frac{1}{\mu_0 \epsilon_0}

Then replacing,

B(2\pi r) = \frac{1}{C^2} (\pi r^2) \frac{d(E)}{dt}

B = \frac{r}{2C^2} \frac{dE}{dt}

Our values are given as

dE = 2150N/C

dt = 5s

C = 3*10^8m/s

D = 0.440m \rightarrow r = 0.220m

Replacing we have,

B = \frac{r}{2C^2} \frac{dE}{dt}

B = \frac{0.220}{2(3*10^8)^2} \frac{2150}{5}

B =5.25*10^{-16}T

Therefore the magnetic field around this circular area is B =5.25*10^{-16}T

3 0
3 years ago
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