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Mashcka [7]
3 years ago
6

Noah en Meryem testen een zonnespiegel, zie de afbeelding. De spiegel bundelt de warmtestraling van de zon naar één punt. Op die

plek hebben ze een zwarte pan met 2,0 kg water gezet. De oppervlakte van de spiegel is 3,0 m2. De warmtestraling van de zon is op een heldere zomerdag 1,0 kW m−2. De spiegel weerkaatst hiervan 80%.
Norah en Meryem willen dat de temperatuur van het water met 80 °C stijgt. Neem aan dat het water 50% van alle warmtestraling die op de pan valt opneemt. De warmtecapaciteit van water is 4,18∙103 J kg−1 K−1.

Hoeveel minuten duurt dit opwarmen?
Physics
1 answer:
Harlamova29_29 [7]3 years ago
6 0

Answer:

a lo que estás viendo me parece que es 80% por qué si no viene se que soy de sexto de primaria

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5 0
3 years ago
A 3.25 kg block is sent up a ramp inclined at an angle θ = 32.5 ° from the horizontal. It is given an initial velocity v 0 = 15.
vodomira [7]

Answer:

17.11m

Explanation:

Weight of the block is mg=3.25\times 9.8=31.85N, g=9.8N/kg

#Component of the weight acting normal to ramp is:

31.85Ncos \theta=31.85cos 32.5\\=26.862N

#Component of the weight acting parallel to the ramp and against block's motion :

31.85Nsin\theta=31.85Nsin 32.5\textdegree\\=17.113N

Force of kinetic friction parallel to ramp and against block's motion:

\mu_k=0.382\\=>0.382\times 26.862N=10.2613N\\

F_n_e_t=10.2613+17.113=21.3743N

We can now calculate deceleration up incline:

a=F_n_e_t/m\\=21.3743/3.25\\=6.5767m/s^2

#The time,t, of block's motion up incline is given as:

t=V_O/a\\=15.0/6.5767\\=2.2808s

v_a_v_g=(15+0)/2=7.5m/s\\\\d=v_a_v_g(t)=7.5\times2.2808\\=17.1058m

The block moves 17.11m up the incline.

7 0
3 years ago
Are mushrooms, producers, consumers, or decomposers?
swat32
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8 0
3 years ago
Are heat lamps are designed to reheat food when food falls under 135 degrees?
Serjik [45]
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5 0
4 years ago
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A 0.30-m-radius automobile tire accelerates from rest at a constant 2.0 rad/s2. What is the centripetal acceleration of a point
lianna [129]

Answer:

The centripetal acceleration is 30 m/s²

Explanation:

Given that,

Radius = 0.30 m

Acceleration = 2.0 rad/s²

Time = 5.0

We need to calculate the centripetal acceleration

Using formula of angular velocity

\omega=a\times t

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Put the value into the formula

\omega=2.0\times5.0

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a_{c}=30\ m/s^2

Hence, The centripetal acceleration is 30 m/s²

8 0
3 years ago
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