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Dovator [93]
3 years ago
15

Can I get your number so we can talk?

Mathematics
2 answers:
guapka [62]3 years ago
8 0
What do u need to talk about my dude?
solniwko [45]3 years ago
7 0

Answer:

no but you can have my gm/ail

Step-by-step explanation:

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Find the value of in the triangle shown below.<br> 13<br> 12<br> X
Lynna [10]

Answer:

D) 5

Step-by-step explanation:

a²+b²=c²

12²+b²=13²

144+b²=169

b²=169-144

b²=25

b=√25

b=5

5 0
3 years ago
If m\angle A=(6x+10)^{\circ}∠A=(6x+10) ∘ and m\angle B=(4x+30)^{\circ}∠B=(4x+30) ∘ , then find the measure of \angle B∠B.​
netineya [11]

A=6 × + 10=88555%__/455

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3 years ago
The same as has greater then less than plz anwser I am struggling
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For each power of ten , the number of zeros written in the product is the same as the number of exponents.
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3 years ago
You recently sent out a survey to determine if the percentage of adults who use social media has changed from 66%, which was the
il63 [147K]

Answer:

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Of the 2809 people who responded to survey, 1634 stated that they currently use social media.

This means that n = 2809, \pi = \frac{1634}{2809} = 0.5817

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 - 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.56

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 + 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.6034

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

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3 years ago
If the interest earned by a CD is compounded continuously, which rule is most accurate when calculating how long it will take th
malfutka [58]
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