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grin007 [14]
3 years ago
13

How many grams are 1.25 moles of potassium bromide (KBr)?

Chemistry
1 answer:
sukhopar [10]3 years ago
6 0

Answer:

The SI base unit for amount of substance is the mole. one mole is equal to one mole potassium bromide or 119.0023 grams

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Carbon-14 is an isotope used in carbon dating. The nucleus becomes Nitrogen-14 through beta decay. Its half-life is 5370 years.
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Answer:

If the half-life of 14C is 5730 years, when this period of time has passed it will have been halved, it is called the exponential decay law of radioactive isotopes.

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) In another experiment, the student titrated 50.0mL of 0.100MHC2H3O2 with 0.100MNaOH(aq) . Calculate the pH of the solution at
andrew11 [14]

Answer:

Explanation:

moles of acetic acid = 500 x 10⁻³ x .1 M

= 5 X 10⁻³ M

.005 M

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Moles of sodium acetate formed = .005 M

Moles of NaOH left = .095 M

pOH = 4.8 + log .005 / .095

= 4.8 -1.27875

= 3.52125

pH = 14 - 3.52125

= 10.48

6 0
3 years ago
How do moss leaves and fish differ? How are they the same?
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4 0
2 years ago
Which statement best compares and contrasts two physical properties of matter? Density and solubility are similar because they b
mash [69]
I believe the correct answer would be that b<span>oiling points and melting points are similar because they both involve the change in a state of a material, but they are different because boiling point involves a change from a liquid to a gas and melting point involves a change from a solid to a liquid. Boiling and melting are phase changes that can happen to a substance however they differ in the process that happens.</span>
8 0
3 years ago
Read 2 more answers
Consider the reaction: <img src="https://tex.z-dn.net/?f=NiO%28s%29%2BCO%28g%29%20%5Crightleftharpoons%20Ni%28s%29%2BCO_2%28g%29
sasho [114]

Answer:

Molar concentration of CO₂ in equilibrium is 0.17996M

Explanation:

Based on the reaction:

NiO(s) + CO(g) ⇆ Ni(s) + CO₂(g)

kc is defined as:

kc = [CO₂] / [CO] = 4.0x10³ <em>(1)</em>

As initial concentration of CO is 0.18M, the concentrations in equilibrium are:

[CO] = 0.18000M - x

[CO₂] = x

Replacing in (1):

4.0x10³ = x / (0.18000-x)

720 - 4000x = x

720 = 4001x

x = 0.17996

Thus, concentrations in equilibrium are:

[CO] = 0.18000M - 0.17996 = 4.0x10⁻⁵

[CO₂] = x = <em>0.17996M</em>

<em></em>

Thus, <em>molar concentration of CO₂ in equilibrium is 0.17996M</em>

<em />

I hope it helps!

5 0
3 years ago
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