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mel-nik [20]
3 years ago
8

Ammonia forms when hydrogen gas reacts with nitrogen gas according to the equation below. If equal moles of nitrogen and hydroge

n are combined, the maximum number of moles of ammonia that could be formed will be equal to:two thirds the number of moles of hydrogenthe number of moles of hydrogenthe number of moles of nitrogentwice the number of moles of nitrogen
Chemistry
2 answers:
Aleksandr-060686 [28]3 years ago
6 0

Answer:

Two thirds the number of moles of hydrogen

Explanation:

The balanced reaction is

3H₂ + N₂ → 2NH₃

So 1 mol of nitrogen gas reacts completely with 3 moles of hydrogen gas, to produce 2 moles of ammonia.

If equal moles of nitrogen and hydrogen are combined, <em>then hydrogen would be the limiting reactant</em>. Let's say we have 3 moles of each reactant, one mol of N₂ reacts with the 3 moles of H₂ and produces 2 moles of NH₃, and 2 moles of N₂ would remain. So the answer is<em> two thirds the number of moles of hydrogen.</em>

Kamila [148]3 years ago
3 0

Answer:

The number of moles NH3 produced is two thirds of moles of hydrogen.

Explanation:

Step 1: Data given

Number of moles H2 = Number of moles N2

Step 2: The balanced equation

3H2 + N2 → 2NH3

Step 3: Calculate mol NH3 produced

For 1 mol N2 consumed, we need 3 moles of H2, to produce 2 mol of NH3

H2 is the limiting reactant. This will be completely consumed.

N2 is in excess. There will be consumed 1/3 of moles of H2

The mole ratio H2:NH3 = 3:2

The number of moles NH3 produced is two thirds of moles hydrogen.

The number of moles N2 is one third of moles hydrogen.

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How much energy would be produced from the reaction of 2.40 moles hydrogen with 3.95 moles chlorine? ___ H2 + ___ Cl2 ___ HCl ΔH
True [87]

Answer:

How much energy would be produced from the reaction of 2.40 moles hydrogen with 3.95 moles chlorine?

H_2 +  Cl_2 -> 2HCl ,  deltaH = -554 kJ

Explanation:

Given,

2.40 moles hydrogen reacts with 3.95 moles chlorine.

From the balanced chemical equation,

1mol. of H2 reacts with 1mol. of Cl2

then,

2.40mol. of H2 reacts with ----?mol of Cl2

=>2.40 mol. H2 * \frac{1mol. Cl2}{1mol. H2} \\=2.40 mol. Cl2

So, the remaining moles of Cl2 is in excess.

The limiting reagent is--- H2.

1mol. of H2 releases --- 554kJ of energy

then,

2.40mol of H2 releases ---- ?

=>2.40mol * \frac{554kJ}{1 mol.} \\=1329.6kJ

Answer is: deltaH =-1329.6kJ

3 0
3 years ago
You have a sample of each of the following five metals, with the mass and density
Sindrei [870]

Answer:

E) Silver, mass = 420 g, d = 10.5 g/cm.

Explanation:

Hello,

In this case, since the density is defined by:

\rho =\frac{m}{V}

Given the mass and density, we compute the volume via:

V=\rho *m

Thus, for each vase we have:

A) V=135g*2.7g/cm^3=364.5cm^3

B) V=305g*8.92g/cm^3=2720.6cm^3

C) V=240g*7.86g/cm^3=1886.4cm^3

D) V=75g*1.74g/cm^3=130.5cm^3

E) V=420g*10.5g/cm^3=4410cm^3

In such a way, the largest volume corresponds to E) Silver, mass = 420 g, d = 10.5 g/cm.

Best regards.

7 0
3 years ago
2-- What is the [H3O+] in a solution with [OH-] = 1 x 10-12 M?<br>​
Arte-miy333 [17]

Answer:

The answer is 0.01 M

Explanation:

The problem is solved by applying the expression for ionic product of water as follows:

Kw = [H₃O⁺] [OH⁻]

Where Kw is the ionic product of water and it is 1.10⁻¹⁴ M at⁴ 25ºC. As [OH⁻]= 1.10⁻¹² M, [H₃O⁺] will be:

[H₃O⁺]= Kw/ [OH⁻]= 1.10⁻¹⁴M/1.10⁻¹²M= 0.01 M

5 0
3 years ago
What is water clarity and why is it important?
il63 [147K]

Answer:

it's a measure of how far down light can penetrate through the water column. ... Because water clarity is closely related to light penetration, it has important implications for the diversity and productivity of aquatic life that a system can support

6 0
3 years ago
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mr_godi [17]

Answer:

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Explanation:

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