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2 years ago

A car initially traveling at 20 m/s accelerates at a uniform rate of 4.00 m/sec^2 for a displacement of 50 m

1 answer:

4 0

Answer: A car initially traveling at 60 km/h accelerates at a constant rate of 2.0 m/s2. A spaceship far from any star or planet accelerates uniformly from 72 m/s to 160 m/s .

Explanation: i hoped that helped you.

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Two wheels with fixed hubs and radii 0.51 m and 1.9 m, each having a mass of 3 kg, start from rest. Forces 5 N and F2 are applie

Katarina [22]

Answer:

18.63 N

Explanation:

Assuming that the sum of torques are equal

Στ = Iα

First wheel

Στ = 5 * 0.51 = 3 * (0.51)² * α

On making α subject of formula, we have

α = 2.55 / 0.7803

α = 3.27

If we make the α of each one equal to each other so that

5 / (3 * 0.51) = F2 / (3 * 1.9)

solve for F2 by making F2 the subject of the formula, we have

F2 = (3 * 1.9 * 5) / (3 * 0.51)

F2 = 28.5 / 1.53

F2 = 18.63 N

Therefore, the force F2 has to 18.63 N in order to impart the same angular acceleration to each wheel.

3 0

3 years ago

What's the time constant of a 10 H inductor and a 200 ohm resistor connected in series

melamori03 [73]

<h3>Option B</h3><h3>The time constant of a 10 H inductor and a 200 ohm resistor connected in series is 50 millisecond</h3>

<em><u>Solution:</u></em>

Given that,

10 H inductor and a 200 ohm resistor connected in series

To find: time constant

<em><u>The time constant in seconds is given as:</u></em>

$Time\ constant = \frac{L}{R}$

Where,

L is the inductance in henry and R is the resistance in ohms

$Time\ constant = \frac{10}{200}\\\\Time\ constant = 0.05\ seconds$

Convert to millisecond

1 second = 1000 millisecond

0.05 second = 0.05 x 1000 = 50 millisecond

Thus time constant is 50 millisecond

7 0

3 years ago

A cylinder contains 3.5 L of oxygen at 350 K and 2.7 atm . The gas is heated, causing a piston in the cylinder to move outward.

Effectus [21]

Answer:

The pressure is $P_2 = 1.84 \ a.t.m$

Explanation:

From the question we are told that

The first volume of is $v_1 = 3.5 \ L$

The first pressure is $P_1 = 2.7 \ a.t.m$

The first temperature is $T_1 = 350 \ K$

The new temperature is $T_2 = 620 \ K$

The new volume is $V_2 = 9.1 \ a.t.m$

Generally according to the combined gas law we have that

$\frac{P_1 V_1 }{T_1 } = \frac{P_2 V_2 }{T_2 }$

=> $P_2 = \frac{P_1 * V_1 * T_2 }{T_1 * V_2 }$

=> $P_2 = \frac{ 2.7 * 3.5 * 620 }{ 350 * 9.1 }$

=> $P_2 = 1.84 \ a.t.m$

4 0

3 years ago

An object at rest or moving at a constant speed in a straight path will continue to do so unless acted upon by an unbalanced for

Furkat [3]

I believe if your looking for true or false answer, that the answer is true

5 0

2 years ago

What is the restoring force of a spring stretched 0.35 meters with a spring contact of 55 newtons?

Vesna [10]

F=-kx = -19,25 answer D

6 0

3 years ago

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