Question

of benzene is 1.05 J/g°C Calculate the amount of heat (in kJ) necessary to raise the temperature of 53.8 g benzene by 50.6 K. The specific heat capacity of benzene is 1.05 J/g°C 16.6 kJ 2.86 kJ 1.61 kJ 3.85 kJ 2.59 kJ

Answer 1

Answer:

2.86 kJ

Explanation:

When a substance is heated and there's no phase change happening, the amount of heat (Q) necessary for the heating can be calculated by:

Q = m*c*ΔT

Where m is the mass, c is the specific heat capacity of the substance, and ΔT is the variation of temperature. So, in this case, m = 53.8 g, c = 1.05 J/g°C, and ΔT = 50.6 K. The temperature variation is the same in °C and K, so:

Q = 53.8*1.05*50.6

Q = 2858.394 J (÷1000)

Q = 2.86 kJ