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Delicious77 [7]
3 years ago
10

I suck at this stuff. HELP

Chemistry
1 answer:
erastovalidia [21]3 years ago
7 0
What do you need help with
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Find the amount in kJ of heat exchanged by the combustion of 61.9 g of ethane (C2H6(8) given that the molar enthalpy of combusti
elena-14-01-66 [18.8K]

Answer:

2994 kJ

Explanation:

When one mol of ethane (C₂H₆) is combusted, 1451 kJ of heat is exchanged.

First we convert 61.9 g of C₂H₆ into moles, using its molar mass:

  • 61.9 g ÷ 30 g/mol = 2.06 mol C₂H₆

Finally we <u>calculate how much heat is exchanged by the combustion of 2.06 moles of C₂H₆</u>:

  • 2.06 mol * 1451 kJ/mol = 2994 kJ
8 0
3 years ago
How many molecules of water in 61.0 grams of h2o​
trapecia [35]
I’m not 100% sure but I think it’s 1098
6 0
3 years ago
Read 2 more answers
Using two different instruments I measured the length of my foot to be 27 centimeters and 27.00 centimeters. Explain the differe
Sophie [7]

Answer:

As you used two diferent instruments, one is more sensitive than the other.

Explanation:

The sensitivity of an instrument is the minimum amount of magnitude that can be  differentiate a measurement system.

In method A, you got 27 cm, so if in method B, you got 27.00, method B is more sensitive. It's like saying that one system measures more than the other

8 0
3 years ago
Aluminum has a density of 2.70 g/mL. A sample of aluminum weighs 67.5 g. If this sample is put into a graduated cylinder that ha
romanna [79]

Answer:

60 ml

Explanation:

Now, we know that density = mass/volume

Mass of aluminium = 67.5 g

volume of aluminium =?

density of aluminium = 2.70 g/mL

volume of aluminium = mass/density = 67.5/2.70 = 25 ml

Since volume of water in the cylinder = 35 ml

The water rises to ; 35 ml + 25 ml = 60 ml

4 0
2 years ago
PLEASE ANSWER CORRECTLY FOLLOWING GUIDLINES SO ANSWER WONT GET DELETED I REALLY NEED HELP
blagie [28]

Chemical reaction

equation

reactants

products

yields

mass

balanced

atoms

coefficients

numbers

element

correct

substance

two

Explanation:

did my best lol I'm like 98.69% confident

8 0
2 years ago
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