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Thepotemich [5.8K]
4 years ago
7

When participating in weight training program , which of following is most likely to occur

Health
1 answer:
vova2212 [387]4 years ago
5 0
There are many factors in weight training but most commonly you will gain muscular strength and appearance. 
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Rewrite the following sentences to focus on the positive not the negative
dexar [7]
I set a goal to make my bed every morning this month. I've already done it for 10 days so far. I'm doing pretty well at keeping my resolutions by doing what I said I would! I don't think I'll don't anyone at the event tonight but I'm excited to go and meet new people. I'm sure it will be fun!

Was I allowed to use new words? Hope this helps lol
8 0
4 years ago
What is the second part of step 1 in the IDEAS process, after the problem has been identified?
alex41 [277]
Define the problem
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5 0
4 years ago
The base of a triangle is seven less than twice its
denis23 [38]

Answer:

b=2h-7

Area of a triangle: A=1/2 of bh

replace b with 2h-7: A=(1/2)(2h-7)h=102 => (2h-7)h=204

2h^2-7h-204=0

factor or use quadratic function to solve

h=12

b=2*-7=17

Explanation:

8 0
4 years ago
Prove sinA*cos2A=1/4sin4A*secA<br>​
kolezko [41]

Answer:

The prove is below

Explanation:

From trigonometric identities:

cos2A=cos(A+A)=cos^2A-sin^2A\\sin2A=sin(A+A)=2sinAcosA\\sin4A=sin(2A+2A)=2sin2Acos2A=2(2sinAcosA)(cos^2A-sin^2A)=4sinAcos^3A-4cosAsin^3A\\secA=\frac{1}{cosA}

Therefore:

\frac{1}{4}sin4AsecA = \frac{1}{4}( 4sinAcos^3A-4cosAsin^3A)\frac{1}{cosA}\\= sinAcos^3A-cosAsin^3A(\frac{1}{cosA} )\\=sinAcos^2-sin^3A\\=sinA(cos^2A-sin^2A)\\But\ cos^2A-sin^2A=cos2A\\Therefore:sinA(cos^2A-sin^2A)=sinAcos2A\\\frac{1}{4}sin^4Acos2A=sinAcos2A

4 0
3 years ago
After extended use of the drugs that treat HIV, the virus often becomes resistant and the drugs no longer work.
Tanzania [10]

Answer:

true

Explanation:

3 0
2 years ago
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