1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Drupady [299]
3 years ago
6

Simplest mole ratio for glucose

Chemistry
1 answer:
EastWind [94]3 years ago
4 0

Answer:1. In Glucose: C : H : O = 1 : 2 : 1

2. In Sulfuric acid: H : S : O = 2 : 1 : 4

3. In Butene: C : H = 1 : 2

You might be interested in
How is protenin in milk broken down in our digestive system​
aliina [53]

Answer:

when we drink the milk the digestive system produce protease enzyme to break down the protein of milk.

7 0
3 years ago
Explain how index minerals allow a scientist to understand the history of a metamorphic rock?
Masteriza [31]
It allows a scientist to understand the history of metamorphic rock by estimating the temperature, depth, and pressure at which a rock undergoes metamorphism. Hope that helped!
5 0
3 years ago
Read 2 more answers
3. A magnet attracts a piece of metal. How is this event like a chemical bond?
damaskus [11]

Answer: the answer is b

7 0
2 years ago
Why is wood both renewable and nonrenewable?​
Tasya [4]

Answer:

"Wood is technically a renewable source of energy, since it is a form of biomass. All biomass is traditionally considered a renewable source of energy because it is part of the natural carbon cycle on Earth." I found this from https://www.quora.com/

Explanation:

4 0
3 years ago
Read 2 more answers
Consider the reaction given below.
Drupady [299]

Answer:

  • <u>K =  0.167 s⁻¹</u>

Explanation:

<u>1) Rate law, at a given temperature:</u>

  • Since all the data are obtained at the same temperature, the equilibrium constant is the same.

  • Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

        r = K [A]ᵃ [B]ᵇ

<u>2) Use the data from the table</u>

  • Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

         Divide r₂ by r₁:     [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

  • Use the first and second set of data to find the exponent a:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

        Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

                                  2ᵃ = 2 ⇒ a = 1

         

<u>3) Write the rate law</u>

  • r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

<u>4) Use any set of data to find K</u>

With the first set of data

  • r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K =  0.167 s⁻¹

6 0
4 years ago
Other questions:
  • Based on the table what conclusion can the student make about relationships between elements
    8·1 answer
  • Which compound(s will not form a yellow precipitate when treated with excess iodine in the presence of naoh?
    6·1 answer
  • Mendeleev noticed that certain similarities in the chemical properties of elements appeared at regular intervals when teh elemen
    12·1 answer
  • When 58.5 g of NaCl is dissolved in 1 kg of water, what is the resulting molality?
    15·1 answer
  • What is the ph of a solution of 0.650 m k2hpo4, potassium hydrogen phosphate?
    7·1 answer
  • 1. When recommending solutions to decrease human impact, which location were you able to make the greatest positive impact? Plea
    14·1 answer
  • PLease help me I am giving a lot of points for this please help me
    8·2 answers
  • Please help me I will give you the brain thing and extra points.
    5·2 answers
  • What is it that lives if it is fed, and dies if you give it a drink
    13·2 answers
  • 1q
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!