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Yuri [45]
3 years ago
9

Julie is cycling at a speed of 3.4 meters/second. If the combined mass of the bicycle and Julie is 30 kilograms, what is the kin

etic energy?
Physics
2 answers:
Anon25 [30]3 years ago
6 0
Velocity=3.4m/sec
Mass=30kg
so kinetic energy=1/2mv^2
=1/2×30×3.4×3.4
=15×3.4×3.4
=15×11.56
=173.4 kg m per second square
Oliga [24]3 years ago
5 0

Answer: 173.4 Joules

Explanation: Kinetic energy is the energy possessed by an object by virtue of its motion.

K.E=\frac{1}{2}\times mv^2

m= mass of object

v = velocity

K.E=\frac{1\times 30kg\times (3.4ms^{-1})^2}{2}=173.4kgm^2s^{-2}=173.4J

(1kgm^2s^{-2}=1Joule)

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A force of 350N is applied to a body. If the work done is 40kJ, what is the distance through which the body moved?
Studentka2010 [4]

The distance covered by the body is 114.3 m

Explanation:

The work done by a force exerted on an object is given by

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and of the displacement

For the object in this problem, we have

F = 350 N is the force applied

W=40 kJ = 40,000 J is the work done

\theta=0^{\circ} if we assume that the force is applied parallel to the motion of the object

Solving for d, we find the distance covered by the object:

d=\frac{W}{F cos \theta}=\frac{40,000}{(350)(cos 0)}=114.3 m

Learn more about work:

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7 0
3 years ago
The tape in a videotape cassette has a total
Softa [21]

Answer:

1.37 rad/s

Explanation:

Given:

Total length of the tape is, d= 297 m

Total time of run is, t = 2.1 hours

We know, 1 hour = 3600 s

So, 2.1 hours = 2.1 × 3600 = 7560 s

So, total time of run is, t= 7560 s

Inner radius is, r = 10\ mm = 0.01\ m


Outer radius is, R = 47\ mm = 0.047\ m


Now, linear speed of the tape is, v =\frac{d}{t}=\frac{297}{7560}=0.039\ m/s


Let the same angular speed be \omega.

Now, average radius of the reel is given as the sum of the two radii divided by 2.

So, average radius is, R_{avg}=\frac{R+r}{2}=\frac{0.047+0.01}{2}=\frac{0.057}{2}=0.0285\ m


Now, common angular speed is given as the ratio of linear speed and average radius of the tape. So,

\omega=\dfrac{v}{R_{avg}}\\\\\\\omega=\dfrac{0.039}{0.0285}\\\\\\\omega=1.37\ rad/s


Therefore, the common angular speed of the reels is 1.37 rad/s.

5 0
3 years ago
Why are male genitals outside the body?
BigorU [14]
Because if they were in the inside, then they would not be able to sexually reproduct and could not have offspring. 
7 0
3 years ago
Hiii please help i’ll give brainliest if you give a correct answer please thanks!
lakkis [162]

Answer: the first one

Explanation: good luck!

8 0
3 years ago
Read 2 more answers
In a compound microscope, the objective has a focal length of 1.0 cm, the eyepiece has a focal length of 2.0 cm, and the tube le
expeople1 [14]

Answer:

The  value  is   m \approx   310

Explanation:

From the question we are told that

     The  focal length of the objective is  f_o =  1.0 \ cm

    The  focal length of the eyepiece is  f_e  =  2.0 \  cm

    The  tube length is  L  =  25 \  cm

Generally the magnitude of the overall magnification is mathematically represented as

            m =  m_o  *  m_e

Where  m_o is the objective magnification which is mathematically represented as

        m_o  =  \frac{L}{f_o }

=>      m_o  =  \frac{25}{1 }

=>      m_o  =  25

m_e is the eyepiece magnification which is mathematically evaluated as

     m_e  =  \frac{L }{f_e }

     m_e  =  \frac{25 }{ 2}

      m_e  =  12.5 \  cm

So

    m =  25 * 12.5

     m \approx   310

6 0
3 years ago
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