3 years ago

The table below lists the characteristics of various stars.

Physics

1 answer:

Dafna1 [17]3 years ago

4 0

Answer:

d is the answer

Explanation:

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A child slides down a snow‑covered slope on a sled. At the top of the slope, her mother gives her a push to start her off with a

kirill [66]

Answer:

θ = 13.16 °

Explanation:

Lets take mass of child = m

Initial velocity ,u= 1.1 m/s

Final velocity ,v=3.7 m/s

d= 22.5 m

The force due to gravity along the incline plane = m g sinθ

The friction force = (m g)/5

Now from work power energy

We know that

work done by all forces = change in kinetic energy

( m g sinθ - (m g)/5 ) d = 1/2 m v² - 1/2 m u²

(2 g sinθ - ( 2 g)/5 ) d = v² - u²

take g = 10 m/s²

(20 sinθ - ( 20)/5 ) 22.5 = 3.7² - 1.1²

20 sinθ - 4 =12.48/22.5

θ = 13.16 °

5 0

3 years ago

When electrons in an atom in an excited state fall to lower energy levels, energy is?

dusya [7]

Radiated away as electromagnetic radiation.

5 0

3 years ago

Please i need answer for part d

matrenka [14]

It is c that’s what it is that’s the answer

4 0

2 years ago

Is dimensionally correct equation must be physically correct . Explain your logic behind physically correct equation ?

anyanavicka [17]

An equation can be dimensionally correct but that does not mean that it is physically correct. Explanation is given in the photo.

8 0

1 year ago

Monochromatic light falls on two very narrow slits 0.048 mm apart. Successive fringes on a screen 6.50 m away are 8.5 cm apart n

vfiekz [6]

Answer:

The wavelength is $\lambda = 6.28 *10^{-7}=628 nm$

The frequency is $f = 4.78 Hz$

Explanation:

From the question we are told that

The slit distance is $d = 0.048 \ mm = 4.8 *0^{-5}\ m$

The distance from the screen is $D = 6.50 \ m$

The distance between fringes is $Y = 8.5 \ cm = 0.085 \ m$

Generally the distance between the fringes for a two slit interference is mathematically represented as

$Y = \frac{\lambda * D}{d}$

=> $\lambda = \frac{Y * d }{D}$

substituting values

$\lambda = \frac{0.085 * 4.8*10^{-5} }{6.50 }$

$\lambda = 6.27 *10^{-7}=628 nm$

Generally the frequency of the light is mathematically represented as

$f = \frac{c}{\lambda }$

where c is the speed of light with values

$c = 3.0 *10^{8} \ m/s$

substituting values

$f = \frac{3.0*10^8}{6.28 *10^{-7}}$

$f = 4.78 Hz$

3 0

3 years ago