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ikadub [295]
3 years ago
8

The table below lists the characteristics of various stars.

Physics
1 answer:
Dafna1 [17]3 years ago
4 0

Answer:

d is the answer

Explanation:

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A car traveling at 50 m/s uniformly accelerates to 60 m/s over an 58 second interval. What is the displacement?
yawa3891 [41]

Explanation:

here u = 50m/s

v = 60m/s

t = 58 s

then a = (60-50)/58 m/s2

= 0.17m/s2

now s= ut+1/2at2

so , 50×58+0.5×0.17×(58)^2 m

= 3185.94 m

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The impulse experienced by a body is equivalent to the body’s change in?
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3 years ago
Which graph best represents the relationship between the conductivity and the temperature of semiconductors ?​
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Answer: I think the answer is B

Explanation:

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In which situation is the gravitational force between two objects hard to detect? (Options)
svlad2 [7]

A - the objects are too small

GRAVITATIONAL FORCE IS EXPERIENCED BY ALL OBJECTS IN THE UNIVERSE ALL THE TIME. BUT THE ORDINARY OBJECTS YOU SEE EVERY DAY HAVE MASSES SO SMALL THAT THEIR ATTRACTION TOWARD EACH OTHER IS HARD TO DETECT. -https://www.ftsd.org/cms/lib6/MT01001165/Centricity/ModuleInstance/630/CHAPTER_2_NOTES_FOR_EIGHTH_GRADE_PHYSICAL_SCIENCE.pdf

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A submarine is stranded on the bottom of the ocean with its hatch 21.0 m below the surface. calculate the force (in n) needed to
Tanzania [10]

Answer:

28,400 N

Explanation:

Let's start by calculating the pressure that acts on the upper surface of the hatch. It is given by the sum of the atmospheric pressure and the pressure due to the columb of water, which is given by Stevin's law:

p_{top} = p_{atm} + \rho g h=1.013\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(21.0 m)=3.071 \cdot 10^5 Pa

On the lower part of the hatch, there is a pressure equal to

p_{bot}=p_{atm}=1.013\cdot 10^5 Pa

So, the net pressure acting on the hatch is

p=p_{top}-p_{bot}=3.071 \cdot 10^5 Pa - 1.013\cdot 10^5 Pa=2.058 \cdot 10^5 Pa

which acts from above.

The area of the hatch is given by:

A=\pi r^2 = \pi (\frac{0.420 m}{2})^2=0.138 m^2

So, the force needed to open the hatch from the inside is equal to the pressure multiplied by the area of the hatch:

F=pA=(2.058\cdot 10^5 Pa)(0.138 m^2)=28,400 N

8 0
3 years ago
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