1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ikadub [295]
3 years ago
8

The table below lists the characteristics of various stars.

Physics
1 answer:
Dafna1 [17]3 years ago
4 0

Answer:

d is the answer

Explanation:

You might be interested in
Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1200 kg and was approaching at
igomit [66]

To resolve point A and B we need the concepts related to conservation of momentum (By collision) and Kinetic Energy. Conservation of momentum is given by the equation,

m_1\vec{v_1}+m_2\vec{v_2} = (m_1+m_2)\vec{v}

Our values in the statment are:

m_1 = 1200kg

v_1 = 6m/s

m_2 = 900kg

v_2 = 24m/s

Part A) As it is in an icy intersection, there is two different components (x,y) then,

1200(-6\hat{j})+900(-24\hat{i}) = (1200+900)\vec{v}

2100\vec{v} = -21600\hat{i}-7200\hat{j}

\vec{v} = -72/7\hat{i}-24/7\hat{j}

Then the magnitude is,

|\vec{v}| = 9.6525m/s

Part B) To obtain the Kinetic Energy Loss we need to use its equation, which is given by,

KE_i = \frac{1}{2}m_1v_1^2+\frac{1}{2}m_2v_2^2

KE_i = \frac{1}{2}(1200)(6)^2+\frac{1}{2}(900)(24)^2

KE_i = 280.8kJ

The final energy is given by,

KE_f = \frac{1}{2}(m_1+m_2)v_f^2

KE_f = \frac{1}{2} (1200+900)(9.65)

KE_f =97778.625J

Then the change in Kinetic Energy is

\Delta KE = KE_f-KE_i = 97.778kJ- 280.8kJ

\Delta KE = -183.02kJ

<em>There was a loss of KE of 183.02kJ</em>

5 0
3 years ago
Plz and I don't know this plz help me​
zvonat [6]

Answer:

Newton

it is derived of mass and displacement

3 0
3 years ago
Read 2 more answers
A photon with wavelength λ = 0.0830 nm is incident on an electron that is initially at rest. if the photon scatters in the backw
QveST [7]
Compton scattering equation of wavelengths 
λ'-λ = h/mec (1 - CosФ)
λ' = λ + h/mec (1 - cos 180°)
= ( 0.0830nm) + (6.626 × 10⁻³⁴ J.s)/ (9.1 × 10⁻³¹ kg)(3.0 × 10⁸ m/s
= 0.0830nm
The momentum of electron is
P photon λ = Pe + P phpton λ'
Pe = h/λ - ( -h/λ') = h(λ' + λ)/λλ'
= (6.626 × 10⁻³⁴ J.s)(( 0.08785nm) +( 0.0883nm)/0.08785nm)( 0.083nm)
1.55 × 10⁻²³ kg.m/s.
7 0
3 years ago
Determine whether the interference is constructive or destructive at each location indicated.
OlgaM077 [116]

Answer:

A. Constructive

B. Destructive

C. Destructive

D. Constructive

Explanation:

Constructive interference takes place at locations along the path of two superposed waves where the waves are in phase such that a high or low point of one of the waves corresponds with a high or low point of the other wave which gives a resulting wave amplitude which is the sum of the amplitudes of the individual waves

Destructive interference takes place at locations along the path of two superposed waves where one wave is out of phase with the other wave such that a high or low point of one of the waves coincides with a low or high point of the other wave respectively thereby cancelling the effect of the other wave and giving a resulting wave that has an amplitude which is the difference in the amplitudes of the individual waves

Therefore;

At point A, the peak of each wave partially coincides resulting in constructive interference

At point B, the peak of the blue wave and the trough of the red wave partially coincides resulting in destructive interference

At point C, the through of the blue wave and the peak of the back wave partially coincides resulting in destructive interference

At point D, the trough of each wave partially coincides resulting in constructive interference.

6 0
2 years ago
A 1 kg ball and a 10 kg ball are dropped from a height of 10 m at the same time. In the absence of air resistance,
RideAnS [48]

Answer:

the two balls will hit the ground at the same time.

Explanation:

The time of dropping, in the following equation, is related to both the distance travel s and the gravitational acceleration g, which are the same for both ball (if we neglect air resistance), no matter what their mass are.

s = gt^2/2

t^2 = 2s/g

So the time it takes to drop 2 balls are the same. They will hit the ground at the same time.

3 0
3 years ago
Other questions:
  • [9]
    10·1 answer
  • What is one difference between an electromagnetic wave and a mechanical wave?
    8·2 answers
  • The sun's rays are directly overhead at the ________ on or about december 21.
    14·1 answer
  • A favorable entropy change occurs when δs is positive. what can be said about the order of the system when δs is positive?
    6·1 answer
  • Moons are natural satellites. They do not orbit the Sun directly. Instead, they move in an orbit around a celestial body, such a
    9·2 answers
  • A pump is partially submerged in oil and is supported by 4 springs. The oil has a specific gravity of 0.90, the weight of the pu
    5·1 answer
  • When a mass of
    9·1 answer
  • Convection with potassium permanganate what would the water in the tube look like if you left this for a few hours
    12·1 answer
  • What direction would the north pole of a bar magnet point if you were to hang the bar magnet from a thin string?.
    9·1 answer
  • Is a motor polarized or not?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!