Carbon dioxide emissions from, well, whatever emits CO2 really.
The answer is 79.9 g.
Copper takes 92.0% of aluminum bronze and it is a limiting factor. We have aluminum in excess, so we need to make a proportion.
If 73.5 g of copper are 92.0%, how many g of aluminum bronze will be 100%:
73.5 g : 92.0% = x : 100%.
x = 73.5 g : 100% * 92.0%
x = 79.9 g
Therefore, from 73.5 g of copper and 6.4 g of aluminum (since 79.9 g - 73.5 g = 6.4 g), maximum 79.9 g of aluminum bronze can be prepared.
3.8mL of 0.42 phosphoric acid is required.
Reaction
2H3PO4 + 3CaCL3 → Ca3(PO)4 + 6HCl
moles CaCl2 =0.16 mol/L x0.010 L = 0.0016 mol
moles of H3Po4
= 0.0016mol of CaCl2 x 2 mole of H3PO4/3mole of CaCl2
= 0.00106 mol
V of H3PO4 = 0.0016/0.42 = 0.0038L = 3.8mL
V of H3PO4=3.8mL
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A laboratory report is an important part of the scientific process that communicate the important work that has been done.
<h3>How to depict the laboratory report?</h3>
Your information is incomplete. Therefore, an overview of a laboratory report will be given. The laboratory report is important for future studies a d experiments.
A laboratory report is broken down intosections such as title, abstract, introduction, methods, materials, results, discussion conclusion, and references.
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Complete Question
The complete question is shown on the first uploaded image
Answer:
The bond angle is 104.48⁰
Explanation:
The explanation is shown on the second uploaded image
