There are 3 moles of water formed in the complete combustion of ethane.
<h3>What is Combustion Reaction? </h3>
Combustion is a chemical reaction between substances , usually including oxygen and usually accompanied by the generation of heat and light in form of flame.
For example , the wood burning in a fireplace. The wood is a fuel which continuously react with oxygen in the air in a combustion reaction.
When ethane goes for combustion
reaction ,
C2H6+7/2 O2→2CO2+ 3H2O
As you can see on the above reaction 3 moles of water molecules are produced .
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Answer:
1,1,1
decomposition reaction
Explanation:
The reaction equation is given as:
_Ca(OH)₂ → _CaO + _H₂O
This reaction is a decomposition reaction in which a single reactant breaks down to give two or more products.
To balance the equation, we assign variables a, b and c, then we use a mathematical approach to solve the problem;
aCa(OH)₂ → bCaO + cH₂O
Conserving Ca : a = b
O: 2a = b + c
H: 2a = 2c
let a = 1, b = 1 , c = 1
Answer:
0.1 moles of magnesium
Explanation:
Mg(s) + 2CH3COOH(aq) -------> Mg(CH3COO)2(aq) + H2(g)
Since the reaction is 1:2 in mole ratio,
1 mole of magnesium reacts with 2 moles of ethanoic acid
x moles of magnesium will react with 0.2 moles of ethanoic acid
2x = 0.2
x = 0.2/2 = 0.1 moles of magnesium used
Answer:
0.57 M
Explanation:
rate = change in concentration /time
Initial concentration of Cl2O5 = 1.16 M
Let the concentration of Cl2O5 after 5.70 seconds be y
rate = (1.16 - y)/5.7
The reaction follows a first order
Therefore, rate = ky = 0.184y
0.184y = (1.16 - y)/5.7
0.184y × 5.7 = 1.16 - y
1.0488y + y = 1.16
2.0488y = 1.16
y = 1.16/2.0488 = 0.57 M
Concentration of Cl2O5 after 5.70 seconds is 0.57 M
