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dem82 [27]
3 years ago
6

1. Why is outside air mixed with return air?​

Engineering
1 answer:
Dmitrij [34]3 years ago
3 0

Answer:

Explanation:

outside air must be mixed with return air at some point in time because here is an example a warm current of air comes in contact with a cold current of air  the warm current has to cool down so it could mix with the cold current or if they don´t mix they would continue to bump into each other and probably cause a tornado. probably.

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A city emergency management agency and a construction company have formed a public-private partnership. The construction company
Goryan [66]

Answer:

B

Explanation:

4 0
3 years ago
Problem 3.10 One/half million parts of a certain type are to be manufactured annually on dedicated production machines that run
goldenfox [79]

Answer:

  • 4 machines
  • 4 machines

Explanation:

(a) The production schedule is 4000 hour per year, or 240,000 minutes. In that time, 133,333 1/3 parts can be produced. The production of 500,000 parts in a year will require the use of ...

  .5 million/(.1333... million/machine) = 3.75 machines

The demand can be satisfied by 4 machines.

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(b) If availability is 95% then 3.75/0.95 ≈ 3.95 machines will be required.

The demand can be satisfied by 4 machines.

8 0
3 years ago
Read 2 more answers
A steady stream (1000 kg/hr) of air flows through a compressor, entering at (300 K, 0.1 MPa) and leaving at (425 K, 1 MPa). The
AleksandrR [38]

Answer:

The work furnished by the compressor is 69.77kJ/s

The minimum work required for the state to change is 55.26kW

Explanation:

The explanation to these solution is on the first, second , third and fourth uploaded image respectively

8 0
3 years ago
What tool is used to measure aggregates in laying tools<br>​
denpristay [2]

Answer:

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6 0
2 years ago
Air enters a control volume operating at steady state at 1.2 bar, 300K, and leaves at 12 bar, 440K, witha volumetric flow rate o
topjm [15]

Answer:

Heat transfer = 2.617 Kw

Explanation:

Given:

T1 = 300 k

T2 = 440 k

h1 = 300.19 KJ/kg

h2 = 441.61 KJ/kg

Density = 1.225 kg/m²

Find:

Mass flow rate = 1.225 x [1.3/60]

Mass flow rate = 0.02654 kg/s

mh1 + mw = mh2 + Q

0.02654(300.19 + 240) = 0.02654(441.61) + Q

Q = 2.617 Kw

Heat transfer = 2.617 Kw

4 0
3 years ago
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