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Romashka-Z-Leto [24]
3 years ago
9

Single-use earplugs require a professional fitting before they can be used.

Engineering
1 answer:
Musya8 [376]3 years ago
8 0
What are you asking? are you asking if it is true or false? sorry :(( i can help you tho!
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The purpose of the pin-indexing system for compressed gas cylinders is to: Select one: A. ensure that the correct regulator is u
dimulka [17.4K]

The purpose of the pin-indexing system for compressed gas cylinders is to ensure that the correct regulator is used for the cylinder. Thus, Option A is the correct statement.

<h3>What is the purpose of PIN indexing system for cylinders?</h3>

The pin index system refers to a safety system designed to make sure the suitable gas is filled into the suitable cylinder, and that the cylinder will most effectively connect with the correct equipment. The positions of the holes at the cylinder valve correspond with the pins suited for the yoke connected to the equipment.

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PLZZ HELP ILL GIVE BRAINLYEST PLZZ HELP
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3 years ago
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Put these expressions in a small program that will demonstrate whether they are true or false. Paste the code, and output from t
love history [14]

complete question:

Put these expressions in a small program that will demonstrate whether they are true or false. Paste the code, and output from the program into your submission. Use if statements and output a message indicating that the expression is True or False.

a = 5,  b = 4,  c = 3,  d = 2 ;

(a <= b + 1 )

(a < b && c > b)

(a >= c || d >= 5)

( !(a > b) )

( b >= a && ! (d < b) )

Answer:

a = 5

b = 4

c = 3  

d = 2

if a <= b + 1 :

       print("True")

else :

      print("False")

if a < b and c > b :

      print("True")

else :

      print("False")

if a >= c or d >= 5:

       print("True")

else :

       print("False")

if not(a > b):

       print("True")

else :

       print("False")

if ( b >= a and not(d < b) ):

       print("True")

else :

      print("False")

Explanation:

I used python to write the code

The equivalent of && in python is and while the equivalent of || is or. The equivalent of !  is not  in python .

I wrote an if statement to print True for each expression if it is actually true and the else statement print False if the expression is actually false.

For example the first expression says if a is less than or equal to b + 1(5). This statement is actually true so the expression will print True. a is 5 and b plus 1 is 5, so a is equal to 5 which is true.

if a < b and c > b :

Both expression must be true for the if statement to print True.  a is not less than b and c is not greater than b so the expression amount to False.

if a >= c or d >= 5:

One expression must be true for the expression to be True. a >= c is true and d >= 5 is false. So the expression amount to True.

not(a > b)

This simply means negate the statement a > b . This gives False.

( b >= a and not(d < b))

b >= a is false

d < b is true

not(d < b) is false

false and false is definitely False

6 0
3 years ago
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