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liberstina [14]

3 years ago

12

Dissolved in many gasolines are cleaning agents and anti-knock additives. These cleaning agents and additives are an example of

1 answer:

lorasvet [3.4K]3 years ago

3 0

Solutes

Explanation:

These cleaning agents and additives are examples of solutes.

Solutes are substances that dissolves in other substances called solvents to form a solution.
The solutes are the cleaning agents and anti-knock additives.
The solvents are the gasoline.
When solutes dissolves in solvents they form solutions.
A solution is a mixture that is homogeneous.
For a solute dissolve in a solvent, they must both have the same property.
Like substances will only dissolve in like ones.

learn more:

Heterogeneous mixtures brainly.com/question/1446244

#learnwithBrainly

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Two cars are traveling along a straight line in the same direction, the lead car at 25 m/s and the other car at 35 m/s. At the m

Phoenix [80]

Answer:

a. $t_1=12.5\ s$

b. $a_2=-13.61\ m.s^{-2}$ must be the minimum magnitude of deceleration to avoid hitting the leading car before stopping

c. $t_2=2.5714\ s$ is the time taken to stop after braking

Explanation:

Given:

speed of leading car, $u_1=25\ m.s^{-1}$

speed of lagging car, $u_{2}=35\ m.s^{-1}$

distance between the cars, $\Delta s=45\ m$

deceleration of the leading car after braking, $a_1=-2\ m.s^{-2}$

a.

Time taken by the car to stop:

$v_1=u_1+a_1.t_1$

where:

$v_1=0$ , final velocity after braking

$t_1=$ time taken

$0=25-2\times t_1$

$t_1=12.5\ s$

b.

using the eq. of motion for the given condition:

$v_2^2=u_2^2+2.a_2.\Delta s$

where:

$v_2=$ final velocity of the chasing car after braking = 0

$a_2=$ acceleration of the chasing car after braking

$0^2=35^2+2\times a_2\times 45$

$a_2=-13.61\ m.s^{-2}$ must be the minimum magnitude of deceleration to avoid hitting the leading car before stopping

c.

time taken by the chasing car to stop:

$v_2=u_2+a_2.t_2$

$0=35-13.61\times t_2$

$t_2=2.5714\ s$ is the time taken to stop after braking

7 0

3 years ago

What is the final velocity of a car that starts at 22 m/s and accelerates at 3.78 m/s for distance of 45 m

Pepsi [2]

v^2 = v0^2 +2ad v^2 = 22^2 + 2*3.78*45 = 824.2 v= √824.2 = 28.7 m/s

5 0

3 years ago

Most people can detect frequencies as high as 20 000 Hz. Assuming the speed of sound in air is 345 m/s, determine the wavelength

Gekata [30.6K]

Wavelength = speed / frequency

(345 m/s) / (20,000 Hz) = 0.017 m

6 0

3 years ago

Read 2 more answers

When you measure something in meters cubed, you are measuring ____.

Shalnov [3]

I think your answer is volume

7 0

3 years ago

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The speed of light in air is 3 x 108 m/s. The speed of light in ice is 2.29 x 108 m/s. What is the refractive index from air to

Studentka2010 [4]

Answer:

η = 1.31

Explanation:

The formula for the refractive index of from air to some other medium is given by the following formula:

$\eta = \frac{c}{v}\\$

where,

η = refractive index = ?

c = speed of light in air = 3 x 10⁸ m/s

v = speed of light in ice = 2.29 x 10⁸ m/s

Therefore, using these values in the equation we get:

$\eta = \frac{3\ x\ 10^8\ m/s}{2.29\ x\ 10^8\ m/s} \\$

<u>η = 1.31</u>

4 0

2 years ago