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Snezhnost [94]
3 years ago
14

Balance the equation. Mg3(PO4)2+? C → ? Mg3P2+? CO , using the smallest possible integers. What is the sum of the coefficients i

n the balanced equation?1. 14.
2. 16.
3. 12.
4. 18.
5. 22.
Chemistry
1 answer:
Nuetrik [128]3 years ago
8 0

Answer:

Sum of coefficients in balanced equation is 18

Explanation:

Unbalanced equation: Mg_{3}(PO_{4})_{2}+C\rightarrow Mg_{3}P_{2}+CO

Balance O: Mg_{3}(PO_{4})_{2}+C\rightarrow Mg_{3}P_{2}+8CO

Balance C: Mg_{3}(PO_{4})_{2}+8C\rightarrow Mg_{3}P_{2}+8CO

Balanced equation:Mg_{3}(PO_{4})_{2}+8C\rightarrow Mg_{3}P_{2}+8CO

Sum of coefficients in balanced equation = (1+8+1+8) = 18

So, option (4) is correct.

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Answer:

Option C:- that is equal to mass of an proton.

Explanation:

Protons and neutrons have approximately the same mass, about 1.67 × 10-24 grams, which scientists define as one atomic mass unit (amu) or one Dalton. While electron has mass of 9.31 ×10⁻¹⁹.

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4. Energy can be conserved by -
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Energy can be conserved by efficient energy use.

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3 years ago
Which example is the site of reduction when the dry cell is operating
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4 0
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Read 2 more answers
Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s
bazaltina [42]

<u>Answer:</u> The time taken by the reaction is 84.5 seconds

<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{9}=0.077s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}     ......(1)

where,

k = rate constant  = 0.077s^{-1}

t = time taken for decay process = 50.7 sec

[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process =  0.0741 M

Putting values in equation 1, we get:

0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}

[A_o]=3.67M

Now, calculating the time taken by using equation 1:

[A]=0.0055M

k=0.077s^{-1}

[A_o]=3.67M

Putting values in equation 1, we get:

0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s

Hence, the time taken by the reaction is 84.5 seconds

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3 years ago
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