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Answer:
170. g C₇H₅(NO₂)₃
General Formulas and Concepts:
<u>Chemistry - Stoichiometry</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
RxN: C₇H₈ (l) + 3HNO₃ (aq) → C₇H₅(NO₂)₃ (s) + 3H₂O (l)
Given: 69.0 g C₇H₈ (Toluene)
<u>Step 2: Identify Conversions</u>
Molar Mass of C - 12.01 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of C₇H₈ - 7(12.01) + 8(1.01) = 92.15 g/mol
Molar Mass of C₇H₅(NO₂)₃ - 7(12.01) + 5(1.01) + 3(14.01) + 6(16.00) = 227.15 g/mol
<u>Step 3: Stoichiometry</u>
<u /> = 170.085 g C₇H₅(NO₂)₃
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
170.085 g C₇H₅(NO₂)₃ ≈ 170. g C₇H₅(NO₂)₃