Ask question

Ask question

All categories

3 years ago

11

Filtration, decantation, and evaporation are examples of

1 answer:

Tju [1.3M]3 years ago

4 0

<span>An element is made of only one kind of atom, while a compound contains the atoms of two or more elements. For example, gold is made of only one kind of atom, so it is an element, but water is a mix of hydrogen and oxygen, so it is a compound.</span>

You might be interested in

Help me fill this page with the right answer please (17 lines minimum please)

nignag [31]

I am water molecule
I have to first bear the heat of sun .
Then the heat evaporates me into vapours
I am send to the atmosphere with my brothers
Then I have to form clouds
Then precipitation or density of our brothers increases
We keep increasing
Then once a time comes when we are full
We then condensed down to earth
We comes back in the form of rain
Then either we are stored in some place or underground
Then people collects us from different places like pond,river etc

7 0

2 years ago

Read 2 more answers

Where does oxidation occur in an electrochemical cell?

AlladinOne [14]

Option No. 1 at the cathode in both an electrolytic cell and a voltaic cell

Negative ion arrives at the anode, attracted by electrostatic forces, where they lose electrons. Loss of electrons is defined as oxidation.

The reverse process occur at the negative electrode, where positive ions pick up electrons. They are reduced.

8 0

4 years ago

Read 2 more answers

Monochloroacetic acid (HC2H2ClO2) is a skin irritant that is used in "chemical peels" intended to remove the top layer of dead s

yaroslaw [1]

<u>Answer:</u> The pH of the solution is 1.703

<u>Explanation:</u>

We are given:

Concentration of monochloroacetic acid = 0.31 M

The chemical equation for the dissociation of monochloroacetic acid follows:

$HC_2H_2ClO_2\rightleftharpoons H^++C_2H_2ClO_2^-$

<u>Initial:</u> 0.31

<u>At eqllm:</u> 0.31-x x x

The expression of $K_a$ for above equation follows:

$K_a=\frac{[H^+][C_2H_2ClO_2^-}}{[HC_2H_2ClO_2]}$

We are given:

$K_a=1.35\times 10^{-3}$

Putting values in above equation follows:

$1.35\times 10^{-3}=\frac{x\times x}{(0.31-x)}\\\\x=-0.021,0.0198$

Neglecting the negative value of 'x' because concentration cannot be negative.

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

$pH=-\log (0.0198)\\\\pH=1.703$

Hence, the pH of the solution is 1.703

5 0

4 years ago

A mixture of MgBr2 and inert material is analyzed to determine the Mg content. First the mixture is dissolved in water. Then all

Mumz [18]

Answer:

9.24% the percent of Mg in the mixture.

Explanation:

Mass of silver bromide = 1.1739 g

Moles of silver bromide = $\frac{1.1739 g}{188 g/mol}=0.006244 mol$

1 mole of AgBr has 1 mole of bromine atom.Then 0.006244 moles AgBr has 0.006244 mole bromine atom.

Moles of bromine atoms = 0.006244 moles

Magnesium bromide has 2 moles of bromine atom.Then 0.006244 moles of bromine atoms will be in :

$\frac{0.006244 mol}{2}=0.003122 mol$

Magnesium bromide has 1 mole magnesium atom, then 0.003122 moles of magnesium bromide will have :

$1\times 0.003122 mol=0.003122 mol$ magnesium atom

Mass of 0.003122 moles of magnesium :

0.003122 mol × 24 g/mol = 0.07493 g

Mass of the sample = 0.8107 g

Percentage of magnesium in the sample ;

$=\frac{0.07493 g}{0.8107 g}\times 100=9.24\%$

9.24% the percent of Mg in the mixture.

8 0

3 years ago

A sample of ideal gas at room temperature occupies a volume of 27.0 L at a pressure of 852 torr . If the pressure changes to 426

Lubov Fominskaja [6]

The new volume V₂ is 5.4L

The new volume is calculated using Boyle's law formula

That is P₁V₁=P₂V₂

where,

p₁ = 852 torr

V₁ = 27.0

P₂ = 4260 torr

V₂=?

Make V₂ the subject of the formula by diving into both sides of the equation by P₂

V₂ = P₁V₁/P₂

⇒ 852 *

V₂ is, therefore, = 5.4 L

Learn more about Boyle's law here: brainly.com/question/1696010

#SPJ4

5 0

2 years ago