3 years ago

A spring has been compressed inside a toy what kind of energy is this

Physics

1 answer:

zlopas [31]3 years ago

4 0

Answer:

Elastic Potential Energy

Explanation:

Elastic Potential Energy (“Spring Energy”) is the form of energy an object has when it is stretched, compressed, twisted, bent, or otherwise has its shape changed as long as the object resists and will try to return to its original state.

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A force F₁ of magnitude 6.50 units acts at the origin in a direction 49.0° above the positive x axis. A second force F₂ of magni

Sergeu [11.5K]

Found this hope it helps

4 0

3 years ago

a ball is projected with a certain angle with initial velocity u. it covers horizontal range R. With what initial velocity it mu

Elena L [17]

Answer:

1.5 u

Explanation:

The range equation is:

R = u² sin(2θ) / g

When u = v, R = 2.25 R.

2.25 R = v² sin(2θ) / g

2.25 u² sin(2θ) / g = v² sin(2θ) / g

2.25 u² = v²

1.5 u = v

8 0

3 years ago

A 55-kg block, starting from rest, is pushed a distance of 5.0 m across a floor by a horizontal force Fp whose magnitude is 140

max2010maxim [7]

Answer:

The answer is "151.25 J and -547.64 J".

Explanation:

$u = 0\\\\v = 2.35\ \frac{m}{sec}\\\\d = 5.0 \ m\\\\$

Using formula:

$v^2 = u^2 + 2 \times a \times d\\\\2.35^2 = 0^2 + 2 \times a \times 5\\\\a = \frac{2.35^2}{10} \\\\$

$= 0.55 \ \frac{m}{sec^2}\\\\$

$F_{net} = m \times a\\\\F_{net} = 55 \times 0.55 = 30.25\ N\\\\$

Calculating the Work by net force

$W = F_{net}\times d\\\\W = 30.25 \times 5 = 151.25 \ J\\\\$

The above work is converted into thermal energy.

Now,

$F_{net} = F_p - F_f\\\\F_p = 140 \ N\\\\F_f = u_k\times m \times g = u_k \times 55 \times 9.81\\\\F_f = 539.55 \times u_k\\\\30.25 = 140 - u_k \times 55 \times 9.81\\\\u_k = \frac{(140 - 30.25)}{(55\times 9.81)}\\\\uk = 0.203 = \text{Coefficient of friction}\\\\W_f = -F_f \times d\\\\W_f = -0.203 \times 55 \times 9.81 \times 5\\\\Work\ done\ by\ friction = -547.64 \ J$