** You pull a rope oriented at a 37° angle above the horizontal. The other end of the rope is attached to the front of the first
of two wagons that have the same 30-kg mass. The rope exerts a force of magnitude T1 on the first wagon. The wagons are connected by a second horizontal rope that exerts a force of magnitude T2 on the second wagon. Determine the magnitudes of T1 and T2 if the acceleration of the wagons is 2.0 m⁄s2.
1 answer:
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Answer: F = 102141N
Explanation: <em><u>Newton's 2nd Law</u></em> states that a force can change the motion of a body. The relation is given by
F = m.a
whose units are:
[F] = N
[m] = kg
[a] = m/s²
Jenny's car, at the moment of the break, had acceleration:
a = 78.57 m/s²
Then, Force is
F = 1300*78.57
F = 102141 N
<u>Jenny's car experienced a force of </u><u>magnitude 102141N.</u>
Answer:
"1155 N" is the appropriate solution.
Explanation:
Given:
Acceleration,
Forces resisting motion,
Mass,
By using Newton's second law, we get
⇒
Or,
⇒
By putting the values, we get
⇒
⇒
⇒