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Paha777 [63]
3 years ago
11

.

Physics
1 answer:
bija089 [108]3 years ago
6 0

Cathode rays are negatively charged

Explanation:

Thomson's cathode ray beam bent towards the positively charged plate. With this information, he was able to conclude that the rays were negatively charged.

Cathode rays were discovered by J.J. Thomson based on his experiment on the gas discharge tube. He was able to discover some of the properties of the wave.

One notable one was that he observed that the rays deflected towards the positively charged plate.

Since unlike poles attract then he concluded that the cathode rays were negatively charged.

learn more:

Rutherford brainly.com/question/1859083

#learnwithBrainly

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A rocket car on a horizontal rail has an initial mass of 2500 kg and an additional fuel mass of 1000 kg. At time t0 the rocket m
slamgirl [31]

Answer: Acceleration of the car at time = 10 sec is 108 m/s^{2} and velocity of the car at time t = 10 sec is 918.34 m/s.

Explanation:

The expression used will be as follows.

M\frac{dv}{dt} = u\frac{dM}{dt}

\int_{t_{o}}^{t_{f}} \frac{dv}{dt} dt = u\int_{t_{o}}^{t_{f}} \frac{1}{M} \frac{dM}{dt} dt

       = u\int_{M_{o}}^{M_{f}} \frac{dM}{M}

v_{f} - v_{o} = u ln \frac{M_{f}}{M_{o}}

v_{o} = 0

As, v_{f} = u ln (\frac{M_{f}}{M_{o}})

u = -2900 m/s

M_{f} = M_{o} - m \times t_{f}

           = 2500 kg + 1000 kg - 95 kg \times t_{f}s

           = (3500 - 95t_{f})s

v_{f} = -2900 ln(\frac{3500 - 95 t_{f}}{3500}) m/s

Also, we know that

     a = \frac{dv_{f}}{dt_{f}} = \frac{u}{M} \frac{dM}{dt}

        = \frac{u}{3500 - 95 t} \times (-95) m/s^{2}

        = \frac{95 \times 2900}{3500 - 95t} m/s^{2}

At t = 10 sec,

v_{f} = 918.34 m/s

and,   a = 108 m/s^{2}

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A diffraction grating produces a first-order bright fringe that is 0.18 m away from the central bright fringe on a flat screen.
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Answer:

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Solution:

As per the question:

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Now,

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