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prisoha [69]
3 years ago
5

Which material has a greater density, lead or feathers?

Chemistry
1 answer:
algol133 years ago
5 0

Lead has a higher density


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Determine the value of the equilibrium constant, KgoalKgoalK_goal, for the reaction CO2(g)⇌C(s)+O2(g)CO2(g)⇌C(s)+O2(g), Kgoal=?
NISA [10]

Answer:

The value of the equilibrium constant for reaction asked is 1.24\times 10^{-7}.

Explanation:

CO_2(g)\rightleftharpoons C(s)+O_2(g)

K_{goal}=?

K_{goal}=\frac{[C][O_2]}{[CO_2]}

2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2(g)..[1]

K_1=\frac{[CH_3COOH][O_2]^2}{[CO_2]^2[H_2O]^2}

2H_2(g)+O2(g)\rightleftharpoons 2H_2O(l)..[2]

K_2=\frac{[H_2O]^2}{[H_2]^2[O_2]}

CH_3COOH(l)\rightleftharpoons 2C(s)+2H_2(g)+O_2(g)..[3]

K_3=\frac{[C]^2[H_2]^2[O_2]}{[CH_3COOH]}

[1] +  [2] + [3]

2CO_2(g)\rightleftharpoons 2C(s)+2O_2(g)

 ( on adding the equilibrium constant will get multiplied with each other)

K=K_1\times K_2\times K_3

K=5.40\times 10^{-16}\times 1.06\times 10^{10}\times 2.68\times 10^{-9}

K=1.53\times 10^{-14}

K=\frac{[C]^2[O_2]^2}{[CO_2]^2}

On comparing the K and K_{goal}:

K^2=K_{goal}

K_{goal}=\sqrt{K}=\sqrt{1.53\times 10^{-14}}=1.24\times 10^{-7}

The value of the equilibrium constant for reaction asked is 1.24\times 10^{-7}.

4 0
3 years ago
Given the following equation, what is the correct form of the conversion factor needed to convert the number of moles of O₂ to t
djverab [1.8K]

Answer : The correct option is (c) \frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2}

Explanation :

The given balanced chemical reaction is,

4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)

From the balanced chemical reaction, we conclude that

As, 3 moles of O_2 react to give 2 mole of Fe_2O_3

So, 1 mole of O_2 react to give \frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2} moles of Fe_2O_3

Thus, the conversion factor needed to convert the number of moles of O_2 to the number of moles of Fe_2O_3 produced is \frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2}

Hence, the correct option is (c) \frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2}

7 0
3 years ago
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